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If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=

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If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=  [#permalink]

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New post Updated on: 11 Jun 2015, 13:25
2
2
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

67% (00:56) correct 33% (00:57) wrong based on 286 sessions

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If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=

A. 27
B. 9
C. 3
D. 1
E. 1/3

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Originally posted by reto on 11 Jun 2015, 13:15.
Last edited by Bunuel on 11 Jun 2015, 13:25, edited 1 time in total.
Edited the question.
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If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=  [#permalink]

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New post 11 Jun 2015, 13:24
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Re: If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=  [#permalink]

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New post 11 Jun 2015, 13:28
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If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=  [#permalink]

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New post Updated on: 04 Jun 2016, 14:59
1
I first thought the question stem said 3x^2 - Y. So, i guess everyone should be careful and note that there is no subtraction sign but that it is a multiplication (*) sign--- meaning : 3x^2 * Y.

Regardless of that note, yes the answer is 9! (B)

Originally posted by acarpio1 on 04 Jun 2016, 14:57.
Last edited by acarpio1 on 04 Jun 2016, 14:59, edited 1 time in total.
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Re: If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=  [#permalink]

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New post 07 Jan 2019, 12:52
I haven't understood the question stem itself, can someone explain theoretically what does the question actually imply? :cry:
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Re: If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=  [#permalink]

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New post 07 Jan 2019, 23:15
1
Shef08 wrote:
I haven't understood the question stem itself, can someone explain theoretically what does the question actually imply? :cry:


If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=

A. 27
B. 9
C. 3
D. 1
E. 1/3

Symbol ∇ here indicates a function, which does the following: for any two numbers x and y, x∇y equals to 3x^2*y. For example, if x = 5 and y = 10, then 5∇10 = 3*5^2*10 = 750.

The question asks to find the value of 1∇(1∇1). First deal with expression in brackets: (1∇1) = 3*1^2*1 = 3. So, now we should find the value of 1∇3, which is 3*1^2*3 = 9.

Answer: B.

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Re: If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=   [#permalink] 07 Jan 2019, 23:15
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