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19 May 2022, 02:45
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
62% (01:58) correct
38%
(01:59)
wrong
based on 239
sessions
History
Date
Time
Result
Not Attempted Yet
If x, y, and z are consecutive positive integers greater than 1, not necessarily in that order, then which of the following is (are) true?
I. x > z
II. x+ y > z
III. yz > xz
IV. xy > y + z
(A) I only
(B) II only
(C) II and III only
(D) II and IV only
(E) III and IV only
I. x > z
II. x+ y > z
III. yz > xz
IV. xy > y + z
(A) I only
(B) II only
(C) II and III only
(D) II and IV only
(E) III and IV only
19 May 2022, 12:01
Kudos
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Bunuel
Breaking Down the Info:
I. We don't know the order of x, y, and z. Insufficient.
II. We can try making z the biggest. Then x = z - 2 and y = z - 1. Plugging in gives 2z - 3 > z and z > 3, which has to be true since z was the biggest integer (the smallest z, in that case, is z = 4).
III. We can eliminate z since it is positive, to get y > z. Again we don't know the order so this is insufficient.
IV. We can make left side bigger by letting x = 4, y = 3, z = 2. We can also make right side bigger by letting x = 2, y = 3, and z = 4. Insufficient.
Then only II is always true.
Answer: B
17 Sep 2025, 23:41
Kudos
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