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MathRevolution
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MathRevolution
If x, y, and z are positive integers, is x+y divisible by 3?

1) x+z is divisible by 3
2) y+z is divisible by 3

1) (x+z)/3 = int.
Nothing about y. Insufficient.

2) (y +z)/3 - int.
Nothing about x. Insufficient.

1+2)
(x+y+2z)/3 = int.
x = 1, y=1, z=2
(x+y)/3 = not int.

x=2, y=1, z=3
(x+y+2z)/3 = int.
(x+y)/3 = int.

Insufficient. E is the answer.
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MathRevolution
If x, y, and z are positive integers, is x+y divisible by 3?

1) x+z is divisible by 3
2) y+z is divisible by 3

Asked: If x, y, and z are positive integers, is x+y divisible by 3?

1) x+z is divisible by 3
x + z mod 3 = 0
Since y is unknown
NOT SUFFICIENT

2) y+z is divisible by 3
y + z mod 3 = 0
Since x is unknown
NOT SUFFICIENT

(1) + (2)
1) x+z is divisible by 3
x + z mod 3 = 0
2) y+z is divisible by 3
y + z mod 3 = 0
x + y + 2z mod 3 = 0
x - y mod 3 = 0
There is no way to find x+ymod3
NOT SUFFICIENT

IMO E
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