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If x, y, and z represent consecutive integers, and x < y < z, which of
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18 Jul 2018, 00:43
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Re: If x, y, and z represent consecutive integers, and x < y < z, which of
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18 Jul 2018, 01:32
Bunuel wrote: If x, y, and z represent consecutive integers, and x < y < z, which of the following equals y? Let, x = 1, y = 2, z = 3 : since x < y < z Putting respective values in given cases, each one of case is satisfied. I. x + 1 > y = x + 1 > 2 = 1 + 1 = 2 II. (x +z)/2 > y = (x + z)/2 > 2 = 4/2 = 2 III. (x + y + z)/3 > y = (1 + 2 + 3) / 3 = 2 Hence, E.
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Re: If x, y, and z represent consecutive integers, and x < y < z, which of
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18 Jul 2018, 01:56
Bunuel wrote: If x, y, and z represent consecutive integers, and x < y < z, which of the following equals y?
I. x + 1 II. (x +z)/2 III. (x + y + z)/3
A. I only B. I and II only C. I and III only D. II and III only E. I, II and III Assigning different values for consecutive integers x< y< z. x = 2 y= 3 z = 4. I. x+1 = y 2+1 = 3 II. (x+z)/2 = y (2+4)/2 = 3 III. (x+y+z) /3 = y (2+3+4) / 3 =3 All the options are correct. Note: Consecutive integers can be negative. Same rules. The best answer is E.



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Re: If x, y, and z represent consecutive integers, and x < y < z, which of
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18 Jul 2018, 03:09
Solution Given:• x, y, and z represent consecutive integers • x < y < z To find:• Among the three given options, which equals y. Approach and Working: x, y, and z are consecutive integers. • Hence, y= x+1 and z= x+2 Now, look at every option. I. x + 1= y Hence, x+1 is equal to y.
II.\(\frac{(x +z)}{2}= \frac{x+x+2}{2}\)= 2x+2= x+1 Hence,\(\frac{(x+z)}{2}\) is equal to y.
III. \(\frac{(x + y + z)}{3}= \frac{x+x+1+x+2}{3}= \frac{3x+3}{3}\)= x+1 Hence, \(\frac{(x + y + z)}{3}\) is equal to y. Hence, the correct answer is option E. Answer: E
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Re: If x, y, and z represent consecutive integers, and x < y < z, which of
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22 Jul 2018, 18:35
Bunuel wrote: If x, y, and z represent consecutive integers, and x < y < z, which of the following equals y?
I. x + 1 II. (x +z)/2 III. (x + y + z)/3
A. I only B. I and II only C. I and III only D. II and III only E. I, II and III The easiest way to solve this problem is pick numbers for x, y, z. So let x = 2, y = 3, and z = 4. We see that y = x + 1. So I is true. Since (x + z)/2 = (2 + 4)/2 = 3, we see that II is also true. Finally, since (x + y + z)/3 = (2 + 3 + 4)/3 = 3, we see that III is also true. Answer: E
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Re: If x, y, and z represent consecutive integers, and x < y < z, which of &nbs
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