Bunuel
If x > y, then what is the value of \(\frac{3^x}{3^y}\) ?
(1) \(2^{3x -3y} = 64\)
(2) x and y are consecutive odd numbers.
Given: x > y Target question: What is the value of \(\frac{3^x}{3^y}\)? This is a good candidate for rephrasing the target question.
\(\frac{3^x}{3^y} = 3^{x-y}\)
To determine the value of \(3^{x-y}\), we need only determine the value of \(x - y\)
REPHRASED target question: What is the value of \(x-y\) ? Statement 1: \(2^{3x -3y} = 64\) Rewrite as follows: \(2^{3x -3y} = 2^6\)
Since the bases are equal, the exponents must be equal: \(3x-3y=6\)
Divide both sides of the equation by 3 to get:
\(x-y = 2\)Since we can answer the
REPHRASED target question with certainty, statement 1 is SUFFICIENT
Statement 2: x and y are consecutive ODD numbers We know that consecutive odd integers differ by 2.
Since it's given that x > y, we know that
\(x-y = 2\)Since we can answer the
REPHRASED target question with certainty, statement 2 is SUFFICIENT
Answer: D
VIDEO ON REPHRASING THE TARGET QUESTION: