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If x + y = z, is the average (arithmetic mean) of x, y and z greater

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Joined: 02 Sep 2009
Posts: 43917
If x + y = z, is the average (arithmetic mean) of x, y and z greater [#permalink]

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New post 09 Jan 2018, 22:31
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Difficulty:

  45% (medium)

Question Stats:

47% (01:07) correct 53% (01:32) wrong based on 19 sessions

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Re: If x + y = z, is the average (arithmetic mean) of x, y and z greater [#permalink]

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New post 09 Jan 2018, 23:08
Bunuel wrote:
If x + y = z, is the average (arithmetic mean) of x, y and z greater than z ?

(1) x > 0
(2) z > 0


x+y=z. Avg of x, y, z= (x+y+z)/3 = (z+z)/3 = 2z/3. Question asks whether 2z/3 > z Or 2z > 3z or 3z - 2z < 0. Thus the question is basically asking whether z < 0 or not.

(1) x > 0. This doesnt tell us anything about the sign of z. Insufficient.

(2) z > 0. So obviously z is not less than 0. This gives us NO as an answer to the question. Sufficient.

Hence B answer
Re: If x + y = z, is the average (arithmetic mean) of x, y and z greater   [#permalink] 09 Jan 2018, 23:08
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If x + y = z, is the average (arithmetic mean) of x, y and z greater

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