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x^2 + y^2 = 1

st1:
xy = 0
So either x is 0, or y is 0.

If x is 0, y^2 = 1, y is either 1 or -1. x+y could be 1 or -1.
If y is 0, x^2 = 1, x is either 1 or -1. x+y could be 1 or -1.
Insufficient.

St2:
y is 0, so x is either 1 or -1. x+y could be 1 or -1.
Insufficient.

St1 & St2:
x is still either 1 or -1. x+y could be 1 or -1.
Insufficient.

Ans E
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singh_amit19
If x2 + y2 =1, is x + y =1?
(1) xy =o
(2) y = 0

(A)Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)EACH statement ALONE is sufficient.
(E)Statements (1) and (2) TOGETHER are NOT sufficient

-------------------------------------------------------------------------
This a easy one....i picked A

X^2+Y^2+2XY = 1 + 2XY = 1 (if (1) info is given)
X=+/- 1 if (2) given

so A

Please post any other views????

Stmnt1
Here it means either x or y is 0 . So that would end up as either
x = (+/-) 1 or y = (+/-) 1 . Dont get anything from here. A insuff.

Stmnt2
x = +/- 1 . So B is insuff too. Its just like stmnt 1 .

Combining , I dont think still we can prove x+y = 1 .
I would give E.


E .. That was good one.. A common trap for these types of questions..
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I thought ans is A??

x^2 + y^2 = 1
(x+y)^2 - 2xy = 1
x+y = 1
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singh_amit19
If x2 + y2 =1, is x + y =1?
(1) xy =o
(2) y = 0

(A)Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)EACH statement ALONE is sufficient.
(E)Statements (1) and (2) TOGETHER are NOT sufficient

-------------------------------------------------------------------------
This a easy one....i picked A

X^2+Y^2+2XY = 1 + 2XY = 1 (if (1) info is given)
X=+/- 1 if (2) given

so A

Please post any other views????


I say E.

for x^2+y^2=1. Then x or y has to be 0. now is x+y=1?

Starting w/ S2 b/c its easier.

S2:
y=0. 1^2+0=1 -1^2+0=1. so 1+0=1, but -1+0 dsnt =1... insuff.


S1:
xy=0 well -1*0=0 or 1*0=0. Same logic as in S1 when apply to the problem. Insuff.

1 and 2: again values could be 1,0 or -1,0 or vice versa.


Insuff.



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