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what about the case x=y? if x=y then x will cancel Y and answer will be 3, which is greater than 2 and it is prime number

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If y ≠ 3 and 3x/y is a prime integer greater than 2, which of the following must be true?
Ⅰ. x = y
Ⅱ. y = 1
Ⅲ. x and y are prime integers.
(A) None
(B) Ⅰ only
(C) Ⅱonly
(D) Ⅲonly
(E) Ⅰand Ⅲ

Guys, I am sure this might have come earlier, but I am kind of confused about these MUST be true questions.

Here, if 3x/y is a prime number greater than 2 then x and y should always be equal so that they can cancel out. We cant have any other factor of 3x/y!!

There are other possibilities here: 3 might be a factor of y, and might therefore cancel in the fraction, leaving us with a prime that comes from the factors of x. For example, if x = 10, and y = 6, then 3x/y = 5. So we can see that none of I, II, or III need to be true.
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what about the case x=y? if x=y then x will cancel Y and answer will be 3, which is greater than 2 and it is prime number

Yes, it *could* be true that x = y, but the question doesn't ask what could be true; it asks what *must* be true. As I pointed out above, it doesn't need to be true that x = y.
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Tricky question. Took 1.50min to solve it.

But this is what I did.

1st Statement: From first looking at the expression, 'x=y' is the easiest way to have a Prime Integer greater > 2 (3 in this case) from the original question stem. Now we must ask ourselves, is there anyway that this number is a prime number greater than 2 and different from 3? Say for example 5. First look at the denominator, to have 5 as the answer we need to get rid of the 3 so 'y=3', could be an option. Then if 'x = 5, we have that the expression is in fact 5.

So x/y = 5/3 could be an option.

2nd Statement: Does 'y=1" ? We just found out that 'y=3' is an option so this one is out.

3rd Statement: This is a bit more difficult. We need to ask ourselves again, do they both have to be prime integers? Let's start with the denominator, we used 'y=3' in the last example but 'y' could be in fact any multiple of 3, lets say we picked 6. Now, to have '5' (Prime>2) as an answer we could use 10 in the numerator. Since both 'x' and 'y' are 10 and 6 they don't both have to be prime numbers.

So answer is (a) None
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jlgdr
Tricky question. Took 1.50min to solve it.

But this is what I did.

1st Statement: From first looking at the expression, 'x=y' is the easiest way to have a Prime Integer greater > 2 (3 in this case) from the original question stem. Now we must ask ourselves, is there anyway that this number is a prime number greater than 2 and different from 3? Say for example 5. First look at the denominator, to have 5 as the answer we need to get rid of the 3 so 'y=3', could be an option. Then if 'x = 5, we have that the expression is in fact 5.

So x/y = 5/3 could be an option.

2nd Statement: Does 'y=1" ? We just found out that 'y=3' is an option so this one is out.

3rd Statement: This is a bit more difficult. We need to ask ourselves again, do they both have to be prime integers? Let's start with the denominator, we used 'y=3' in the last example but 'y' could be in fact any multiple of 3, lets say we picked 6. Now, to have '5' (Prime>2) as an answer we could use 10 in the numerator. Since both 'x' and 'y' are 10 and 6 they don't both have to be prime numbers.

So answer is (a) None


The only issue with your response is the prompt explicitly says that y≠3
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jlgdr
Tricky question. Took 1.50min to solve it.

But this is what I did.

1st Statement: From first looking at the expression, 'x=y' is the easiest way to have a Prime Integer greater > 2 (3 in this case) from the original question stem. Now we must ask ourselves, is there anyway that this number is a prime number greater than 2 and different from 3? Say for example 5. First look at the denominator, to have 5 as the answer we need to get rid of the 3 so 'y=3', could be an option. Then if 'x = 5, we have that the expression is in fact 5.

So x/y = 5/3 could be an option.

2nd Statement: Does 'y=1" ? We just found out that 'y=3' is an option so this one is out.

3rd Statement: This is a bit more difficult. We need to ask ourselves again, do they both have to be prime integers? Let's start with the denominator, we used 'y=3' in the last example but 'y' could be in fact any multiple of 3, lets say we picked 6. Now, to have '5' (Prime>2) as an answer we could use 10 in the numerator. Since both 'x' and 'y' are 10 and 6 they don't both have to be prime numbers.

So answer is (a) None


The only issue with your response is the prompt explicitly says that y≠3

You are right appologies, my bad.

So we could just use x=10 and y=6 for all the Statements and there we go.
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TooLong150

Can you explain your reasoning to (I)?

If a prime number is written as a product of two numbers, one of them must be prime and the other must be 1.
3x/y would be prime if 'x/y is 1' (in which case 3x/y = 3) or '3 gets canceled off from a 3 in y and the leftover is a prime number'

So some solutions are:
x = y = 1
x = y = Anything other than 0
y is a multiple of 3, say 3n and x/n is a prime number.

We are given that y is not 3 but we are not given that it is not a multiple of 3. Say, y = 6 = 3n. In that case x/n can be a prime number. e.g. x = 10 or 14 or 26 etc
3x/y = 3*10/6 = 5
3x/y = 3*14/6 = 7
etc

So x = 14, y = 6 is a solution. So it not NECESSARY (but it is possible) that x=y, y = 1, x and y are prime

Answer (A)
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Economist
If y ≠ 3 and 3x/y is a prime integer greater than 2, which of the following must be true?

I. x = y
II. y = 1
III. x and y are prime integers.

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

Make a list of options for \(\frac{3x}{y}\) and solve for x:
\(\frac{3x}{y}\) = 3, 5, 7, 11...
3x = 3y, 5y, 7y, 11y...
x = y, \(\frac{5y}{3}\), \(\frac{7y}{3}\), \(\frac{11y}{3}\)...

If \(x = \frac{5y}{3}\), then it's possible that \(y=4\) and that \(x=\frac{20}{3}\), with the result that I, II, and III are all NOT true.

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Bunuel can you help us here
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Bunuel can you help us here

Check here: https://gmatclub.com/forum/if-y-3-and-3 ... ml#p638293
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Economist
If y ≠ 3 and 3x/y is a prime integer greater than 2, which of the following must be true?

I. x = y
II. y = 1
III. x and y are prime integers.

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

Guys, I am sure this might have come earlier, but I am kind of confused about these MUST be true questions.

Here, if 3x/y is a prime number greater than 2 then x and y should always be equal so that they can cancel out. We cant have any other factor of 3x/y!!




Since this is a ‘Must be true’ kind of question, the best strategy to adopt would be that of trying to falsify each statement once and simultaneously eliminate the corresponding answer options.

Remember that any statement which is false ONCE, cannot be true ALWAYS. In a ‘Must be true’ question, the objective is to identify a statement/statements which is/are true ALWAYS/under all cases.

To make a statement false, we take a few simple cases i.e. simple values for the variables.
The question says that y≠3 and 3x/y is a prime number greater than 2. This means that the possible value for 3x/y can be 3,5,7 and so on.

If 3x/y = 3, then x and y can be any value, but both are equal, since x/y = 1. Statement I is true in this case, so we hold on to options containing statement I i.e. options B and E.

If 3x/y = 5, then x/y = 5/3. One possible value that satisfies this ratio is x = 10 and y = 6. Clearly, all 3 statements are false in this case.

This means that none of them are ALWAYS true. So, the correct answer options is A.

Hope this helps!
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given that y ≠ 3
3x/y is prime >2
must be true
1. x=y yes & no
yes when x=y=3 and no when x=7 & y = 3
2. y=1
yes when x= 1 or any value same as y so not sufficient
3
x & y are prime integers
x=y=3
x=7 ; y = 3
x=35 & y = 5
insufficient
option A none is correct

Economist
If y ≠ 3 and 3x/y is a prime integer greater than 2, which of the following must be true?

I. x = y
II. y = 1
III. x and y are prime integers.

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

Guys, I am sure this might have come earlier, but I am kind of confused about these MUST be true questions.

Here, if 3x/y is a prime number greater than 2 then x and y should always be equal so that they can cancel out. We cant have any other factor of 3x/y!!
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Economist
If y ≠ 3 and 3x/y is a prime integer greater than 2, which of the following must be true?

I. x = y
II. y = 1
III. x and y are prime integers.

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

 
­
i solved in a different way (someone might have posted, not sure!)
3x/y = prime no. > 2 => 3,5,7,11,13......
3x/y = 3 --> x/y = 1 --> x=y (I. is true. But is it "must be true for all cases"?)
3x/y = 5,7,11,13...
=> x/y = 5/3 , 7/3, 11/3, 13/3, ....... (but y not equals to 3 as given)
=> x/y = 10/6, 14/6, 22/6, 26/6........ (multiplied by 2/2 here). We can also multiply by 3/3 and so on!!!
==> All these combinations of x & y (10,6) , (14,6) are ordered pairs for (x,y)

Now analyyse the options.
I. x=y --> True only for 3x/y = 3. Not true for other cases.
II. y=1 -> Not true as seen for ordered pair solutions.
III. x & y are prime nos. --> No, x and y can be 10 & 6!

Hence (A) none.
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