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If y is a positive integer, and x < 5 − y, then what is the least po
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Updated on: 20 Mar 2018, 09:55
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If y is a positive integer, and x < 5 − y, then what is the least possible value of x ? A. 4 B. 1 C. 0 D. 1 E. 4 == Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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Originally posted by Ayush1692 on 20 Mar 2018, 09:44.
Last edited by Bunuel on 20 Mar 2018, 09:55, edited 1 time in total.
Renamed the topic and edited the question.



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If y is a positive integer, and x < 5 − y, then what is the least po
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20 Mar 2018, 10:25
Ayush1692 wrote: If y is a positive integer, and x < 5 − y, then what is the least possible value of x ?
A. 4 B. 1 C. 0 D. 1 E. 4 Don't remove brackets and solve. The question asks for the logic behind absolute value. \(y\) is a positive integer \(x < 5 − y\) LHS is nonnegative  it is positive or 0. Least value for x is ZERO Does RHS work? For LHS to be less than RHS: RHS cannot be negative RHS cannot be 0 RHS must be positive RHS = (5  pos. integer) y could = 4, 3, 2, or 1, and RHS can = (5  y) = 1, 2, 3, 4 That works. The least possible value of x = 0 The absolute value of 0 is 0 Or: the distance of 0 from 0 is 0 Least possible value: x = 0 Answer C == Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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Re: If y is a positive integer, and x < 5 − y, then what is the least po
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17 Jun 2019, 01:29
Since y is a positive integer so y=1,2,3,4,5,...... Now x must be >=0 since modulus of an expression cannot be zero. So, if we put the values of y starting with 5,4,3,2,1, we get 1) y=5 => x<0 (INVALID! as x must be nonnegative) 2) y=4 => x<1 => this implies that magnitude of x must be less than. Option C as value for x satisfies this condition giving us the least possible integer for x. 3) y=3 => x<2 => This option gives us x such that it could be 0 or 1. Here also, 0 is the least possible value for x.
So correct option is C.



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Re: If y is a positive integer, and x < 5 − y, then what is the least po
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06 Jul 2019, 01:16
Why not 1.
Given y = 1 then x < 5  1 x < 4 4 < x < 4
Therefore, the best answer is 1 ?
Kindly advise



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Re: If y is a positive integer, and x < 5 − y, then what is the least po
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04 Aug 2019, 03:15
trailcb wrote: Why not 1.
Given y = 1 then x < 5  1 x < 4 4 < x < 4
Therefore, the best answer is 1 ?
Kindly advise Hey, I also used a similar method and got the answer wrong. Did you figure out why this approach is wrong



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Re: If y is a positive integer, and x < 5 − y, then what is the least po
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04 Aug 2019, 03:54
generis wrote: Ayush1692 wrote: If y is a positive integer, and x < 5 − y, then what is the least possible value of x ?
A. 4 B. 1 C. 0 D. 1 E. 4 Don't remove brackets and solve. The question asks for the logic behind absolute value. \(y\) is a positive integer \(x < 5 − y\) LHS is nonnegative  it is positive or 0. Least value for x is ZERO Does RHS work? For LHS to be less than RHS: RHS cannot be negative RHS cannot be 0 RHS must be positive RHS = (5  pos. integer) y could = 4, 3, 2, or 1, and RHS can = (5  y) = 1, 2, 3, 4 That works. The least possible value of x = 0 The absolute value of 0 is 0 Or: the distance of 0 from 0 is 0 Least possible value: x = 0 Answer C == Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you. Why can't x be a negative integer, in that case it should be 1 i.e. option D.



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Re: If y is a positive integer, and x < 5 − y, then what is the least po
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08 Aug 2019, 18:54
I don't understand why x can't be negative



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Re: If y is a positive integer, and x < 5 − y, then what is the least po
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08 Aug 2019, 19:59
Hi, I believe that the answer choices are wrong.
The least possible value of x is the smallest value that qualifies x < 5 − y (y is a positive number).
y=1 > x<4 > x can be 3 > smallest x = 3



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If y is a positive integer, and x < 5 − y, then what is the least po
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21 Aug 2019, 06:28
Ayush1692 wrote: If y is a positive integer, and x < 5 − y, then what is the least possible value of x ? A. 4 B. 1 C. 0 D. 1 E. 4 == Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you. Can someone confirm if the question did not originally mean to ask the least possible value of x? Bunuel, chetan2uBecause, otherwise, IMO, x can take 3. The stem reads: x < 5  y and y is positive. So, this implies x < 4. So, x >  4. The least possible value that x can take in that case would be 3 (assuming X is also an integer). Otherwise, the answer doesn't make much sense to me > 3 = 3 and it is clearly less than 5  y, when y = 1. So, perhaps, the stem should have read the least possible value of x instead of the least possible value of x. Cheers AA




If y is a positive integer, and x < 5 − y, then what is the least po
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21 Aug 2019, 06:28






