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# If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y

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Intern
Joined: 22 Sep 2016
Posts: 15
If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y  [#permalink]

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Updated on: 16 Oct 2016, 06:28
5
00:00

Difficulty:

25% (medium)

Question Stats:

76% (01:08) correct 24% (02:02) wrong based on 124 sessions

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If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y – 4)/6, then in terms of x, y equals:

A: (x + 8) / 2

B: (x – 8) / 2

C: (-3x) / 2

D: (-3x + 8) / 2

E: (3x – 8) / 2

Originally posted by MarcoL90 on 16 Oct 2016, 06:21.
Last edited by Bunuel on 16 Oct 2016, 06:28, edited 2 times in total.
Edited the question.
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Joined: 02 Sep 2009
Posts: 47898
Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y  [#permalink]

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16 Oct 2016, 06:31
MarcoL90 wrote:
If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y – 4)/6, then in terms of x, y equals:

A: (x + 8) / 2

B: (x – 8) / 2

C: (-3x) / 2

D: (-3x + 8) / 2

E: (3x – 8) / 2

$$\frac{(y^2 – 16)}{(3x)} = \frac{(y – 4)}{6}$$;

$$\frac{(y – 4)(y+4)}{(3x)} = \frac{(y – 4)}{6}$$;

$$\frac{(y+4)}{(3x)} = \frac{1}{6}$$

$$6(y+4)=3x$$;

$$2(y+4)=x$$;

$$y=\frac{x-8}{2}$$.

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Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y  [#permalink]

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28 Nov 2017, 13:50
1
Hi All,

Many Test Takers would approach this question algebraically (which is fine); however, it's designed in such a way that you can also get to the solution by TESTing VALUES (although we are not allowed to use X=4 or Y=0 in our work).

Let's TEST Y = 5.... that makes the equation...

9/3X = 1/6
3X = 54
X = 18

Thus, we're looking for an answer that equals 5 when X=18. There's only one answer that matches...

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Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y &nbs [#permalink] 28 Nov 2017, 13:50
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