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If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y

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If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y [#permalink]

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If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y – 4)/6, then in terms of x, y equals:

A: (x + 8) / 2

B: (x – 8) / 2

C: (-3x) / 2

D: (-3x + 8) / 2

E: (3x – 8) / 2
[Reveal] Spoiler: OA

Last edited by Bunuel on 16 Oct 2016, 06:28, edited 2 times in total.
Edited the question.

Kudos [?]: 3 [0], given: 12

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Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y [#permalink]

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New post 16 Oct 2016, 06:31
MarcoL90 wrote:
If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y – 4)/6, then in terms of x, y equals:

A: (x + 8) / 2

B: (x – 8) / 2

C: (-3x) / 2

D: (-3x + 8) / 2

E: (3x – 8) / 2


\(\frac{(y^2 – 16)}{(3x)} = \frac{(y – 4)}{6}\);

\(\frac{(y – 4)(y+4)}{(3x)} = \frac{(y – 4)}{6}\);

\(\frac{(y+4)}{(3x)} = \frac{1}{6}\)

\(6(y+4)=3x\);

\(2(y+4)=x\);

\(y=\frac{x-8}{2}\).

Answer:B.
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Kudos [?]: 135309 [0], given: 12686

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Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y [#permalink]

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New post 28 Nov 2017, 13:50
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Hi All,

Many Test Takers would approach this question algebraically (which is fine); however, it's designed in such a way that you can also get to the solution by TESTing VALUES (although we are not allowed to use X=4 or Y=0 in our work).

Let's TEST Y = 5.... that makes the equation...

9/3X = 1/6
3X = 54
X = 18

Thus, we're looking for an answer that equals 5 when X=18. There's only one answer that matches...

Final Answer:
[Reveal] Spoiler:
B


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Kudos [?]: 3677 [1], given: 173

Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y   [#permalink] 28 Nov 2017, 13:50
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