It is given that \((z-6)^2\) = 625. Most test takers would just take the square root on both sides and say that z-6 = 25 or – 25.
Instead, if you want to build a process for solving Algebra questions on the GMAT, always keep the RHS as zero and factor out the LHS using common terms or standard algebraic identities.
Therefore, \((z-6)^2\) = 625 can be re-written as \((z-6)^2\) – 625 = 0. Now, it’s common knowledge that 625 =\( (25)^2\), hence the equation can be written as (\(z-6)^2 \)– \((25)^2\) = 0.
This equation is now in the form of\( a^2 – b^2 \)and therefore can be factored out as (a-b) (a+b).
Clearly, a = (z-6) and b = 25. Therefore, (a-b) = (z-6) - 25 = z - 31 and (a+b) = (z - 6) + 25 = z + 19.
Therefore,\( (z-6)^2\) – 625 = 0 can be written as (z – 31) (z + 19) = 0.
Hence, z = 31 or z = -19. The possible values of z + 6 are therefore 37 or -13. Since, -13 is there as one of the options, this has to be our answer.
The correct answer option is C.