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If Z1, Z2, Z3,..., Zn is a series of n consecutive even integers

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If Z1, Z2, Z3,..., Zn is a series of n consecutive even integers [#permalink]

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If \(z_1\), \(z_2\), \(z_3\),..., \(z_n\) is a series of n consecutive even integers, is the sum of the integers in this series a perfect square?

1.) The median of the series is equal to \(4_n\)
2.) \(z_n\) - \(z_1\) = 12
[Reveal] Spoiler: OA

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Concentration: Finance, Accounting
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Re: If Z1, Z2, Z3,..., Zn is a series of n consecutive even integers [#permalink]

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New post 31 Aug 2017, 14:31
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Sum = Average * number of total items

Since the series is consecutive even number = median = average

[1] Average = 4n hence Sum = 4n * n = (2n)^2 - hence Sum is a perfect square

[2] - does not give any info on average
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Kudos [?]: 52 [2], given: 7

Re: If Z1, Z2, Z3,..., Zn is a series of n consecutive even integers   [#permalink] 31 Aug 2017, 14:31
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If Z1, Z2, Z3,..., Zn is a series of n consecutive even integers

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