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In 1991, a box seat at the theater cost $84.50 per ticket, and parking

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In 1991, a box seat at the theater cost $84.50 per ticket, and parking  [#permalink]

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New post 31 Jul 2019, 03:52
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Question Stats:

83% (02:23) correct 17% (02:54) wrong based on 23 sessions

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In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?

A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50

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Re: In 1991, a box seat at the theater cost $84.50 per ticket, and parking  [#permalink]

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New post 31 Jul 2019, 04:06
84.5 — increased by 18%
14.5 — increased by 10%

Calculating the 18% of 84.5:
—> 84.5*(20/100)—84.5(2/100)= 84.5/5– 84.5/50= 16.9–1.69= 15.21

14.5*(10/100)= 1.45
—> 15.21+ 1.45= 16.66

The answer choice is B

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Re: In 1991, a box seat at the theater cost $84.50 per ticket, and parking  [#permalink]

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New post 31 Jul 2019, 04:22
Bunuel wrote:
In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?

A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50



Given: In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. For the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent.

Asked: How much more did it cost one person with one vehicle to spend a night at the theater in 1992?

Increase in ticket cost = $84.5 * 18% = $15.21
Increase in parking cost = $14.5 * 10% = $1.45

Increase in total cost for a person with 1 vehicle = $15.21 + $1.45 = $16.66


IMO B
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In 1991, a box seat at the theater cost $84.50 per ticket, and parking  [#permalink]

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New post 31 Jul 2019, 04:27
Bunuel wrote:
In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?

A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50


Sol:

18 percent of 84.50 is around 15.21
10 percent of 14.50 is 1.45
Total extra cost is 16.66 so option B is the answer
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Re: In 1991, a box seat at the theater cost $84.50 per ticket, and parking  [#permalink]

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New post 31 Jul 2019, 07:25
IMO : B

In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?

A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50

Sol:

18% of 84.50 +10% of 14.50

(20/100)*84.50 - (2/100)84.50 =16.90 - 1.69 = 15.21

then 10% of 14.50 =1.45

so total =15.21+1.45=16.66

Option B.
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Re: In 1991, a box seat at the theater cost $84.50 per ticket, and parking  [#permalink]

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New post 05 Aug 2019, 17:17
Bunuel wrote:
In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?

A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50


A person had to pay 1.18(84.5) + 1.1(14.5) dollars in 1992, whereas he or she had to pay

84.5 + 14.5 dollars in 1991.

Therefore, the increase is:

1.18(84.5) + 1.1(14.5) - (84.5 + 14.5)

Rearranging, we have:

1.18(84.5) - 84.5 + 1.1(14.5) - 14.5

84.5(1.18 - 1) + 14.5(1.1 - 1)

84.5(0.18) + 14.5(0.1)

15.21 + 1.45 = 16.66

Answer: B
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Re: In 1991, a box seat at the theater cost $84.50 per ticket, and parking   [#permalink] 05 Aug 2019, 17:17
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