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31 Jul 2019, 03:52
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B
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Question Stats:
81% (02:18) correct
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In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?
A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50
A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50
31 Jul 2019, 04:06
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84.5 — increased by 18%
14.5 — increased by 10%
Calculating the 18% of 84.5:
—> 84.5*(20/100)—84.5(2/100)= 84.5/5– 84.5/50= 16.9–1.69= 15.21
14.5*(10/100)= 1.45
—> 15.21+ 1.45= 16.66
The answer choice is B
Posted from my mobile device
14.5 — increased by 10%
Calculating the 18% of 84.5:
—> 84.5*(20/100)—84.5(2/100)= 84.5/5– 84.5/50= 16.9–1.69= 15.21
14.5*(10/100)= 1.45
—> 15.21+ 1.45= 16.66
The answer choice is B
Posted from my mobile device
31 Jul 2019, 04:22
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Bunuel
In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?
A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50
A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50
Given: In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. For the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent.
Asked: How much more did it cost one person with one vehicle to spend a night at the theater in 1992?
Increase in ticket cost = $84.5 * 18% = $15.21
Increase in parking cost = $14.5 * 10% = $1.45
Increase in total cost for a person with 1 vehicle = $15.21 + $1.45 = $16.66
IMO B
