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In 1995 Division A of company had 4850 customers. If there

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In 1995 Division A of company had 4850 customers. If there [#permalink]

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20 Aug 2010, 00:58
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In 1995 Division A of company had 4850 customers. If there were 86 service errors in Division A that year, what was service-error rate, in number of service errors per 100 customers, for Division B of Company X in 1995?

(1) In 1995 the overall service-error rate for Division A and B combined was 1,5 errors per 100 customers.
(2) In 1995 Division B had 9,350 customers, none of whom were customers of Division A
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20 Aug 2010, 03:39
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In 1995 Division A of the company had 4850 customers, If there were 86 servise errors in Division A that year,what was servise error rate, in number of servise errors per 100 customers in Division B of the company in 1995?

Question $$\frac{x}{B}100=?$$ Where x is the servise errors in Division B and B is # of customers of division B.

(1) In 1995 the overall service error rate for Division A and B combined was 1,5 errors per 100 customers.

$$\frac{86+x}{4850+B}=\frac{1.5}{100}$$, two variables one equation - can not solve for variables. Also can not get the ratio needed. Not sufficient.

(2) IN 1995 division B had 9350 customers, non of whom were customers for division A

B=9350, clearly insufficient.

(1)+(2) We know the value of B, hence we can calculate x, from (1) and the fraction $$\frac{x}{B}$$. Sufficient.

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Re: in 1995 a division of a company x [#permalink]

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17 Nov 2010, 07:24
Rephrase the question:

Is there sufficient info to know the ratio of errors to customers in division B, if the error ratio for division A is already known?

Statement 1: The Ratio for the two divisions combined is insufficient, because I don't know how much customer overlap there is.

Statement 2: The number of customers in Division B is insufficient because I don't know how many errors there are.

However statement 2 adds that there is no customer overlap, so if I combine the two statements there is sufficient info.

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17 Nov 2010, 07:34
Bunuel wrote:
[b]
(1) In 1995 the overall service error rate for Division A and B combined was 1,5 errors per 100 customers.

$$\frac{86+x}{4850+B}=\frac{1.5}{100}$$, two variables one equation - can not solve for variables. Also can not get the ratio needed. Not sufficient.

In a ratio question, two variables and one equation, can be solved. The issue here is that you cannot simply add the customers of division a and b if you don't know how many overlap

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17 Nov 2010, 11:14
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dwiesenfeld wrote:
Bunuel wrote:
[b]
(1) In 1995 the overall service error rate for Division A and B combined was 1,5 errors per 100 customers.

$$\frac{86+x}{4850+B}=\frac{1.5}{100}$$, two variables one equation - can not solve for variables. Also can not get the ratio needed. Not sufficient.

In a ratio question, two variables and one equation, can be solved. The issue here is that you cannot simply add the customers of division a and b if you don't know how many overlap

Two variables and one equation can be solved for ratio of the variables only when there is no constant term getting added or subtracted.
An equation like $$x + 4850B = 1.5x$$ can be solved for ratio of x and B. But an equation like $$\frac{86+x}{4850+B}=\frac{1.5}{100}$$ cannot be.
The issue here is that you do not have the number of customers of division B. Since the average is weighted, you need to have the number of customers of B to get the error rate of division B. (and in case there is an overlap, then you also need the number of services which were provided together by division A and B and also the overlap in the errors)
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In 1995 Division A of company had 4850 customers. If there [#permalink]

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29 Nov 2017, 06:39
Bunuel wrote:
In 1995 Division A of the company had 4850 customers, If there were 86 servise errors in Division A that year,what was servise error rate, in number of servise errors per 100 customers in Division B of the company in 1995?

Question $$\frac{x}{B}100=?$$ Where x is the servise errors in Division B and B is # of customers of division B.

(1) In 1995 the overall service error rate for Division A and B combined was 1,5 errors per 100 customers.

$$\frac{86+x}{4850+B}=\frac{1.5}{100}$$, two variables one equation - can not solve for variables. Also can not get the ratio needed. Not sufficient.

(2) IN 1995 division B had 9350 customers, non of whom were customers for division A

B=9350, clearly insufficient.

(1)+(2) We know the value of B, hence we can calculate x, from (1) and the fraction $$\frac{x}{B}$$. Sufficient.

Hi Bunuel
The overall service error rate for Division A and B combined was 1,5 errors per 100 customers. Can we just plus the (error rate A/customer A) + (error rate B/customer B)?

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In 1995 Division A of company had 4850 customers. If there   [#permalink] 29 Nov 2017, 06:39
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