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In 2004, 2,400 condos sold, 15% of the total housing units sold that

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In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 16 Aug 2017, 02:02
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Question Stats:

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In 2004, 2,400 condos sold, 15% of the total housing units sold that year. How many units sold in 2004 were not condos?

(A) 16,000

(B) 13,600

(C) 12,400

(D) 11, 200

(E) 8,600

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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 16 Aug 2017, 03:38
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It's a B.
Total no of condos sold is 16000.
So 16000-2400=13600 is answer.

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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 16 Aug 2017, 03:47
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Let the total number of housing unit= x
15% of x are condos and remaining are not condos
15% of x= 2400 =>x= 16000
no of "not condos"= 16000-2400= 13600

Ans- B
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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 16 Aug 2017, 04:01
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It's B
Total no of condos sold is 16000.2400/0.15=16000
So 16000-2400=13600 is answer.
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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 16 Aug 2017, 07:41
condos = 15% of total
so not condos = 85% of total

Now, 15% of total = 2400
85% of total = (?)
i.e. 2400 x 85 / 15
= 13600 (b)
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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 27 Sep 2018, 09:03
Bunuel wrote:
In 2004, 2,400 condos sold, 15% of the total housing units sold that year. How many units sold in 2004 were not condos?

(A) 16,000

(B) 13,600

(C) 12,400

(D) 11, 200

(E) 8,600

Let´s use the "backbone" of our method: connect DATA to FOCUS as soon and as clearly as possible:

\({\text{DATA}}:\,\,\,\,\,2,400\,\,{\text{condos}}\,\,\,\mathop = \limits^{\left( * \right)} \,\,\,\frac{{15}}{{100}}\,\,\left( {{\text{total}}} \right)\)

\({\text{FOCUS}}:\,\,\,? = \frac{{85}}{{100}}\left( {{\text{total}}} \right)\)

\(? = \boxed{\frac{{85}}{{15}}} \cdot \underbrace {\frac{{15}}{{100}}\,\,\left( {{\text{total}}} \right)}_{\left( * \right)\,\,\,2400}\,\, = \,\,\,\frac{{17}}{3}\left( {2400} \right) = \underleftrightarrow {100 \cdot \left( {\frac{{17 \cdot 24}}{3}} \right)}\,\, = \,\,13600\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that  [#permalink]

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New post 02 Oct 2018, 19:51
Bunuel wrote:
In 2004, 2,400 condos sold, 15% of the total housing units sold that year. How many units sold in 2004 were not condos?

(A) 16,000

(B) 13,600

(C) 12,400

(D) 11, 200

(E) 8,600


We can create the following equation in which n = the total number of housing units sold in 2004:

2,400 = 0.15n

2,400/0.15 = n

16,000 = n

Thus, the number of housing units sold that were not condos was 16,000 - 2,400 = 13,600.

Alternate Solution:

We can set up a ratio: if 15% is 2,400, then 85% is x, as follows:

0.15/2400 = 0.85/x

0.15x = 2400 * 0.85

x = (2400 * 0.85)/0.15

x = 13,600

Answer: B
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Re: In 2004, 2,400 condos sold, 15% of the total housing units sold that &nbs [#permalink] 02 Oct 2018, 19:51
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