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In 2012, a store’s average monthly revenue was $20,000. For the rst 1
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20 Jan 2019, 23:45
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In 2012, a store’s average monthly revenue was $20,000. For the first 10 months of the year, the store’s average monthly revenue was $18,000. If the revenue in December was 50% greater than the revenue in November, what was the store’s revenue in November?
Re: In 2012, a store’s average monthly revenue was $20,000. For the rst 1
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21 Jan 2019, 04:15
Bunuel wrote:
In 2012, a store’s average monthly revenue was $20,000. For the first 10 months of the year, the store’s average monthly revenue was $18,000. If the revenue in December was 50% greater than the revenue in November, what was the store’s revenue in November?
A 24,000 B 30,000 C 36,000 D 48,000 E 56,000
Total = 20000 * 12 = 240000.
Total of 10 months = 10 * 18000 = 18000
Revenue of November and December = 240000 - 180000 = 60000.
As per the question : revenue in December was 50% greater than the revenue in November
let the revenue in November is x. Then December = 1.5x.
Re: In 2012, a store’s average monthly revenue was $20,000. For the rst 1
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21 Jan 2019, 06:28
Bunuel wrote:
In 2012, a store’s average monthly revenue was $20,000. For the first 10 months of the year, the store’s average monthly revenue was $18,000. If the revenue in December was 50% greater than the revenue in November, what was the store’s revenue in November?
A 24,000 B 30,000 C 36,000 D 48,000 E 56,000
Total Revenue for the Year 2012 is \(2,40,000\) Total revenue for the first 10 years ( Jan 2012 - Oct 2012 ) is \(1,80,000\)
So, The Revenue for November 2012 & December 2012 is \(60,000\)
Let revenue for Nov be \(x\) , so revenue in Dec is \(\frac{3x}{2}\)
Thus, \(\frac{3x}{2} + x = \frac{5x}{2} = 60,000\)
So, \(x = 24,000\) , Answer must be (A) 24,000 _________________
Thanks and Regards
Abhishek....
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Re: In 2012, a store’s average monthly revenue was $20,000. For the rst 1
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21 Jan 2019, 06:51
Bunuel wrote:
In 2012, a store’s average monthly revenue was $20,000. For the first 10 months of the year, the store’s average monthly revenue was $18,000. If the revenue in December was 50% greater than the revenue in November, what was the store’s revenue in November?
A 24,000 B 30,000 C 36,000 D 48,000 E 56,000
Total sale of store = 20,000 * 12 = 2,40,000
10 months sale = 18,000 * 10 = 1,80,000 nov=x and dec = 1.5x 18*10^4+2.5x = 24*10^4 solve for x = 6* 10^4/2.5 x = 24,000 IMO A
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Re: In 2012, a store’s average monthly revenue was $20,000. For the rst 1
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21 Jan 2019, 06:51
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80% (01:32) correct 
