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In 2015, Ashley invited 12% more people to her annual celebration than

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In 2015, Ashley invited 12% more people to her annual celebration than  [#permalink]

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New post 04 Mar 2019, 14:46
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A
B
C
D
E

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  25% (medium)

Question Stats:

73% (01:52) correct 27% (01:46) wrong based on 41 sessions

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In 2015, Ashley invited 12% more people to her annual celebration than she did in 2014. If every subsequent year Ashley invites 10% more people to her annual celebration than she did the year before, then the number of people she invites in 2017 is approximately what percentage greater than the number of people she invited in 2014 ?

A. 22%
B. 32%
C. 35%
D. 48%
E. 135%

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Re: In 2015, Ashley invited 12% more people to her annual celebration than  [#permalink]

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New post 04 Mar 2019, 22:41
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Solution



Given:
    • In 2015, Ashley invited 12% more people to her annual celebration than she did in 2014.
    • In every subsequent year, Ashley invites 10% more people to her annual celebration than she did the year before.

To find:
    • The number of people she invites in 2017 is approximately what percentage greater than the number of people she invited in 2014.

Approach and Working:
Using the options, we can find the correct answer choice without doing the exact calculation.

    • If we assume the increment to be 10% constant across all the years, then the population on 2017 = 2014 population x 1.1 x 1.1 x 1.1 = 1.331 x 2014 population, which is approximate 33% more than 2014 population.

    • As we assumed the first year’s increase as 10% instead of 12%, the final increased value should be more than 33% but very close to 33% (because the change in 12% to 10% is also very small)

Hence, the correct answer is option C.

Answer: C

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In 2015, Ashley invited 12% more people to her annual celebration than  [#permalink]

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New post 04 Mar 2019, 19:44
Let's suppose she invited 100 people in 2014.
2015 = 1.12(100)
2016 = 112+ 0.1(112) = 123( ignore the decimals)
2017 = 123 + 0.1(123) = 135..

Approximately 35% greater... Option C.

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Re: In 2015, Ashley invited 12% more people to her annual celebration than  [#permalink]

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New post 06 Mar 2019, 03:10
1
let
2014= 100
2015= 112
2016 = 123.2
2017 = 135
~ 35% increase from 2014
IMO C


SajjadAhmad wrote:
In 2015, Ashley invited 12% more people to her annual celebration than she did in 2014. If every subsequent year Ashley invites 10% more people to her annual celebration than she did the year before, then the number of people she invites in 2017 is approximately what percentage greater than the number of people she invited in 2014 ?

A. 22%
B. 32%
C. 35%
D. 48%
E. 135%

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Re: In 2015, Ashley invited 12% more people to her annual celebration than  [#permalink]

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New post 08 Mar 2019, 08:10
1
SajjadAhmad wrote:
In 2015, Ashley invited 12% more people to her annual celebration than she did in 2014. If every subsequent year Ashley invites 10% more people to her annual celebration than she did the year before, then the number of people she invites in 2017 is approximately what percentage greater than the number of people she invited in 2014 ?

A. 22%
B. 32%
C. 35%
D. 48%
E. 135%


We can let n = the number of people Ashley invited in 2014. So we have:

2015 = 1.12n

2016 = 1.12n x 1.1

2017 = 1.12n x 1.1 x 1.1

So the percent increase is:

((1.12n x 1.1 x 1.1) - n)/n x 100

(1.12 x 1.1 x 1.1 - 1) x 100 ≈ 0.35 x 100 = 35%

Alternate Solution:

Let’s assume that Ashley invited 100 people to the celebration in 2014. Thus, in 2015, she invited 1.12 x 100 = 112 people. In 2016 she invited 1.1 x 112 ≈ 123 people, and in 2017 she invited 1.1 x 123 ≈ 135 people.

Using the percent change formula for the years 2017 and 2014, we have:

(135 - 100)/ 100 x 100% = 35%

Answer: C
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Re: In 2015, Ashley invited 12% more people to her annual celebration than   [#permalink] 08 Mar 2019, 08:10
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