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Bunuel
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The information we can get from the question-
A+G+O=61
A<G<O
A/G=G/O if we simplify it we get AxO=G^2


Now we have to use the answer choices to reach the correct answer
Case 1: G=16

AxO=G^2 --------> AxO = 256
A+G+O=61--------> 61-16= 45 = A+O
By prime factorising 256, we take A and O as 8 and 32

8+32+16 = 56 is not equal to 61

Case 2: 20

AxO=G^2 --------> AxO = 400
A+G+O=61--------> 61-20= 41 = A+O
By prime factorising 400, we take A and O as 16 and 25

16+25+20=61, this meets our condition. Hence, G=20

Let's continue to solve other cases to confirm the answer.

Case 3: G=25

AxO=G^2 --------> AxO =500
A+G+O=61--------> 61-25= 36 = A+O
By prime factorising 500, none of the values for A and O will meet the condition

Case 4: G=28

AxO=G^2 --------> AxO =784
A+G+O=61--------> 61-28= 33 = A+O
considering A<G<O, We need O>28 and A<28 and none of the values as part of the prime factorisation of 784 meets this condition.

Case 5: G=30

AxO=G^2 --------> AxO =900
A+G+O=61--------> 61-30= 31 = A+O
considering A<G<O, We need O>30 and there is only one possible value for O that is O=31, then A=1

A+G+O=30+31+1=62 is not the answer.
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