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# In a certain box there're 3 red, 5 blue, and 2 green balls.

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CTO
Joined: 19 Dec 2002
Posts: 250

Kudos [?]: 36 [0], given: 9

Location: Ukraine
In a certain box there're 3 red, 5 blue, and 2 green balls. [#permalink]

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29 Apr 2003, 14:04
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a certain box there're 3 red, 5 blue, and 2 green balls. 6 balls are taken randomly from the box. What is the probability that the taken balls will contain 2 red, 2 blue, and 2 green ones?

Kudos [?]: 36 [0], given: 9

Manager
Joined: 08 Apr 2003
Posts: 149

Kudos [?]: 52 [0], given: 0

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30 Apr 2003, 06:58
Ans is (3C2)(5C2)(2c2)/10C6.

Ans is 1/7

Kudos [?]: 52 [0], given: 0

CTO
Joined: 19 Dec 2002
Posts: 250

Kudos [?]: 36 [0], given: 9

Location: Ukraine

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30 Apr 2003, 13:40
Great, i too have 1/7

Kudos [?]: 36 [0], given: 9

CTO
Joined: 19 Dec 2002
Posts: 250

Kudos [?]: 36 [0], given: 9

Location: Ukraine

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01 May 2003, 13:42

We have a total of 3+5+2 = 10 balls. If we take 6 balls, we have 10C6 total combinations, which equals 210.

Now, the fav combinations are best found the following way: we take each color separately and see how many ways there're to fill the given color's quota with different balls:

Red: 3C2 = 3
Blue: 5C2 = 10
Green: 2C2 = 1

Each combination within a given color we can mix with any other combinations of the two remaining color to get the total combination. For example, if red is filled with balls Red#1 and Red#2, we can mix it with Blue#1 and Blue#2, Blue#1 and Blue#3, etc. So, the total number of fav combinations is a multiplication of those numbers:

Fav = 3 * 10 * 1 = 30
Prob = 30/210 = 1/7

Kudos [?]: 36 [0], given: 9

SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 311 [0], given: 0

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04 May 2003, 23:04
The above is a classical example of so-called hypergeometrical distribution.

Kudos [?]: 311 [0], given: 0

Founder
Joined: 04 Dec 2002
Posts: 15959

Kudos [?]: 29340 [0], given: 5290

Location: United States (WA)
GMAT 1: 750 Q49 V42
Re: probability - 3 colors [#permalink]

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05 Jun 2003, 16:09
gravedigger wrote:
In a certain box there're 3 red, 5 blue, and 2 green balls. 6 balls are taken randomly from the box. What is the probability that the taken balls will contain 2 red, 2 blue, and 2 green ones?

Looks who is around

Kudos [?]: 29340 [0], given: 5290

Re: probability - 3 colors   [#permalink] 05 Jun 2003, 16:09
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# In a certain box there're 3 red, 5 blue, and 2 green balls.

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