Last visit was: 23 Apr 2026, 22:43 It is currently 23 Apr 2026, 22:43
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
Sub 505 (Easy)|   Probability|               
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,802
Own Kudos:
Given Kudos: 105,868
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,802
Kudos: 810,890
 [19]
1
Kudos
Add Kudos
18
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,802
Own Kudos:
810,890
 [3]
Given Kudos: 105,868
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,802
Kudos: 810,890
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
Konstantin1983
Joined: 02 Dec 2014
Last visit: 08 Dec 2021
Posts: 298
Own Kudos:
324
 [3]
Given Kudos: 353
Location: Russian Federation
Concentration: General Management, Economics
GMAT 1: 640 Q44 V33
WE:Sales (Telecommunications)
GMAT 1: 640 Q44 V33
Posts: 298
Kudos: 324
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,063
Own Kudos:
20,000
 [3]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,063
Kudos: 20,000
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

In a certain class, one student is to be selected at random to read. What is the probability that a boy will read?

(1) Two-thirds of the students in the class are boys.
(2) Ten of the students in the class are girls.


In general, when one con is number and the other con is ratio, it is most likely that ratio is an answer. Also, since fraction=proability, que:probability and in 1) 2/3:fraction. Therefore, the answer is A.


-> from con 1) and con 2), if one of the conditions is given by numbers and the other is given by ratio (percent,fraction), then the condition with ratio (percent,fraction) value has higher chance of being the answer.
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
8,710
 [1]
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,710
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
In a certain class, one student is to be selected at random to read. What is the probability that a boy will read?

(1) Two-thirds of the students in the class are boys.
(2) Ten of the students in the class are girls.

We need to determine the probability that a boy will be selected to read, in a class of boys and girls.

Statement One Alone:

Two-thirds of the students in the class are boys.

Since we know that 2/3 of the class are boys, we know that the probability of randomly selecting a boy to read is 2/3. Statement one alone is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone:

Ten of the students in the class are girls.

Without knowing the number of boys in the class, we cannot determine the probability that a boy will be selected to read. Statement two alone is not sufficient to answer the question.

Answer: A
User avatar
susheelh
Joined: 12 Jun 2016
Last visit: 13 Jun 2018
Posts: 144
Own Kudos:
Given Kudos: 151
Location: India
Concentration: Technology, Leadership
WE:Sales (Telecommunications)
Posts: 144
Kudos: 298
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi!

This may sound stupid to ask, but are we not assuming that the student we pick can read? I mean, I could not see anywhere in the stem that says the student we pick is capable of reading.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,802
Own Kudos:
810,890
 [1]
Given Kudos: 105,868
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,802
Kudos: 810,890
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
susheelh
Hi!

This may sound stupid to ask, but are we not assuming that the student we pick can read? I mean, I could not see anywhere in the stem that every student we pick is capable of reading.

It's safe to assume that a student can read...
User avatar
susheelh
Joined: 12 Jun 2016
Last visit: 13 Jun 2018
Posts: 144
Own Kudos:
Given Kudos: 151
Location: India
Concentration: Technology, Leadership
WE:Sales (Telecommunications)
Posts: 144
Kudos: 298
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Thanks Bunuel for the answer!

Its just that this is a DS question. I marked it as E since I thought some of the students can't read. Maybe this happened since I have a young son whom I am still not able to teach how to read :-D

I get it now. Its safe to assume everyone can read.

Bunuel
susheelh
Hi!

This may sound stupid to ask, but are we not assuming that the student we pick can read? I mean, I could not see anywhere in the stem that every student we pick is capable of reading.

It's safe to assume that a student can read...
User avatar
sahilvijay
Joined: 29 Jun 2017
Last visit: 16 Apr 2021
Posts: 289
Own Kudos:
Given Kudos: 76
GPA: 4
WE:Engineering (Transportation)
Products:
Posts: 289
Kudos: 931
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ans is A

1)Let 6x students , then 4x boys
selecting 1 boy out of 4x = 4x and out of 6x is 6x
so P = 4x/6x = 2/3 , Sufficient


2)total number of girls = 10 , insufficient as number of boys are unknown. D eliminated
User avatar
Arsh4MBA
Joined: 19 Jul 2017
Last visit: 14 Oct 2017
Posts: 68
Own Kudos:
Given Kudos: 85
Location: India
Concentration: General Management, Strategy
GPA: 3.5
Posts: 68
Kudos: 26
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
In a certain class, one student is to be selected at random to read. What is the probability that a boy will read?

(1) Two-thirds of the students in the class are boys.
(2) Ten of the students in the class are girls.

Practice Questions
Question: 3
Page: 275
Difficulty: 550


Two-thirds of the students in the class are boys. S1 gives the desired outcome/total possibilities as 2/3. So clearly sufficient.

Statement 2 gives no clue abt the total students or the number of boys. Insufficient.

Ans:A
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,961
Own Kudos:
Posts: 38,961
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109802 posts
498 posts
212 posts