The width of the rectangle is the distance between (-1, -1) and (-1, 1), which is 2. We don't know the length L of the rectangle, but we know the diagonal is 2√5, so using Pythagoras we find
\(\\
\begin{align}\\
2^2 + L^2 &= (2 \sqrt{5} )^2 \\\\
4 + L^2 &= 2^2 (\sqrt{5})^2 \\\\
L^2 &= 20 - 4 \\\\
L^2 &= 16 \\\\
L &= 4\\
\end{align}\\
\)
since L is positive. So the two other points of the rectangle are 4 units horizontally across from the two points D and E that we're given, and the x coordinate of those two points could either be -1 - 4 = -5 if the two unknown points are to the left of D and E, or could be -1 + 4 = 3 if the two unknown points are to the right of D and E. So I imagine the "OA" is "3", but the question has two right answers, while the wording of the question suggests it only has one, so there's a problem with the question.