Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
26 Aug 2010, 06:40
6
44
00:00
A
B
C
D
E
Difficulty:
25% (medium)
Question Stats:
79% (02:35) correct 21% (02:52) wrong based on 1086 sessions
HideShow timer Statistics
In a corporation, 50 percent of the male employees and 40 percent of the female employees are at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
26 Aug 2010, 07:12
11
10
udaymathapati wrote:
In a corporation, 50 percent of the male employees and 40 percent of the female employees are at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
A. 3/5 B. 2/3 C. 3/4 D. 4/5 E. 5/6
Given weighted average employees who are at least 35 years old: \(\frac{0.5m+0.4f}{m+f}=0.42\). Question: \(\frac{f}{m+f}=?\)
I have a different approach that may be useful for you:
Let's say that “x” is the % of male employees in the corporation. So, (1-x) is the % of female employees in the same company. Therefore: \((50%)(x) + (40%)(1-x) = 42%\)
Expressed in fractions: \((1/2)(x) + (2/5)(1-x) = 21/50\)
We solve the equation and we have: \(x = 1/5\)
\((1-x) = 4/5\)
Answer: 4/5 : D
I think I deserve kudos _________________
"Life’s battle doesn’t always go to stronger or faster men; but sooner or later the man who wins is the one who thinks he can."
My Integrated Reasoning Logbook / Diary: http://gmatclub.com/forum/my-ir-logbook-diary-133264.html
In a corporation, 50 percent of the male employees and 40 percent of the female employeesa re at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
a) 3/5
b) 2/3
c) 3/4
d) 4/5
e) 5/6
You can use the weighted averages formula for a 10 sec solution.
No of females/No of males = (50 - 42)/(42 - 40 ) = 4/1
No of females as a fraction of total employees = 4/(4+1) = 4/5
In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
28 Mar 2018, 12:07
VeritasPrepKarishma wrote:
eybrj2 wrote:
In a corporation, 50 percent of the male employees and 40 percent of the female employeesa re at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
a) 3/5
b) 2/3
c) 3/4
d) 4/5
e) 5/6
You can use the weighted averages formula for a 10 sec solution.
No of females/No of males = (50 - 42)/(42 - 40 ) = 4/1
No of females as a fraction of total employees = 4/(4+1) = 4/5
as far i remember the value that is closer to the mean has more weight right? so here # of female employees is more (its not surprising actually, they have always been smarter than men )
how to proceed further ? let me try ...
so 2 here has more weight hence it should be in numerator, and 8 has less weight and should be in denominator
hence
\(\frac{2}{8}\) --> \(\frac{1}{4}\)
so ratio of females to men is 1 to 4 ?
but the mean was closer to percentage of females, shouldnt females be more than men ?
Re: In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
28 Mar 2018, 23:04
2
dave13 wrote:
VeritasPrepKarishma wrote:
eybrj2 wrote:
In a corporation, 50 percent of the male employees and 40 percent of the female employeesa re at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
a) 3/5
b) 2/3
c) 3/4
d) 4/5
e) 5/6
You can use the weighted averages formula for a 10 sec solution.
No of females/No of males = (50 - 42)/(42 - 40 ) = 4/1
No of females as a fraction of total employees = 4/(4+1) = 4/5
as far i remember the value that is closer to the mean has more weight right? so here # of female employees is more (its not surprising actually, they have always been smarter than men )
how to proceed further ? let me try ...
so 2 here has more weight hence it should be in numerator, and 8 has less weight and should be in denominator
hence
\(\frac{2}{8}\) --> \(\frac{1}{4}\)
so ratio of females to men is 1 to 4 ?
but the mean was closer to percentage of females, shouldnt females be more than men ?
The method of allegation is the same as the weighted average formula I have used. To ensure that there is no confusion, use
w1/w2 = (A2 - Aavg)/(Aavg - A1)
No diagram is required here. The details of this are provided in the link given in my post above.
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >
GMAT self-study has never been more personalized or more fun. Try ORION Free!
I wish your website featured search box i wanted to find the link where it is explained whhe sometimes numeratot and denominato values switch places but couldnt find it...
Re: In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
20 Apr 2018, 15:36
udaymathapati wrote:
In a corporation, 50 percent of the male employees and 40 percent of the female employees are at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
A. 3/5 B. 2/3 C. 3/4 D. 4/5 E. 5/6
No. of male=m No. of Female=f
(0.5)*m + (0.4)f = 0.42(m+f) 0.5m + 0.4f = 0.42m + 0.42f 0.08m = 0.02f 8m=2f (multiply both side by 100) 4m=f f/m=4 : 1
In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
23 Apr 2018, 15:08
Alternate way - you can set up two equations:
Males = M and Females = F Set the total to be 100 since we are dealing with percents and no value has been provided.
M+F = 100 (equation 1)
The question says 50% of males and 40% of females are at least 35. The question also says that 42% of total employees are at least 35. .5M + .4F = 42 -> multiply each term by 100 50M+ 40F = 4200 -> reduce down by dividing each by 10 5M+4F= 420 (equation 2)
Subtracting equation 2 from equation 1. You get M=20 and F=80.
Re: In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
01 Sep 2018, 04:54
VeritasKarishma wrote:
eybrj2 wrote:
In a corporation, 50 percent of the male employees and 40 percent of the female employeesa re at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
a) 3/5
b) 2/3
c) 3/4
d) 4/5
e) 5/6
You can use the weighted averages formula for a 10 sec solution.
No of females/No of males = (50 - 42)/(42 - 40 ) = 4/1
No of females as a fraction of total employees = 4/(4+1) = 4/5
Re: In a corporation, 50 percent of the male employees and 40
[#permalink]
Show Tags
11 Sep 2018, 04:34
dave13 wrote:
VeritasPrepKarishma wrote:
eybrj2 wrote:
In a corporation, 50 percent of the male employees and 40 percent of the female employeesa re at least 35 years old. If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?
a) 3/5
b) 2/3
c) 3/4
d) 4/5
e) 5/6
You can use the weighted averages formula for a 10 sec solution.
No of females/No of males = (50 - 42)/(42 - 40 ) = 4/1
No of females as a fraction of total employees = 4/(4+1) = 4/5
as far i remember the value that is closer to the mean has more weight right? so here # of female employees is more (its not surprising actually, they have always been smarter than men )
how to proceed further ? let me try ...
so 2 here has more weight hence it should be in numerator, and 8 has less weight and should be in denominator
hence
\(\frac{2}{8}\) --> \(\frac{1}{4}\)
so ratio of females to men is 1 to 4 ?
but the mean was closer to percentage of females, shouldnt females be more than men ?
I think this is more cleaner
Attachments
2.jpg [ 39.27 KiB | Viewed 1634 times ]
_________________
If you like this post, be kind and help me with Kudos!
close
79% (02:35) correct 
(its not surprising actually, they have always been smarter than men 
let me try ...
