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shrive555
In a group of 100 adults, 75 percent of the women are left-handed. If there are 12 right-handed women in the group, how many men are in the group?

48
52
54
60
62

kindly provide explanation for answer

12 left-handed women compose 100-75=25% (or 1/4) of all women, so there are total of 4*12=48 women --> 100-48=52 men.

Answer: B.
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12 right-handed women -- 25% of all women.
We can find that there are 48 women at all.
100-48=52
(B)
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0.75 x left-handed
0.25 x right-handed = 12
--> x = 48 women
--> number of men = 100 - 48 = 52
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Let x represent the number of men in the group. The sum of all the women and men is 100.

75% of x are left-handed, so the 12 right-handed men represent 25% (1/4) of x.

Therefore, x = 12*4 = 48

The number of woman in the group is 100 - 48 = 52.
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shrive555
In a group of 100 adults, 75 percent of the women are left-handed. If there are 12 right-handed women in the group, how many men are in the group?

A. 48
B. 52
C. 54
D. 60
E. 62

Since 75% of the women are left-handed, the 12 right-handed women constitute 25% of the women. Letting w = the total number of women, we can create the equation:

0.25w = 12

w = 48, so the number of men is 52.

Answer: B
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Let number of women = w; number of men = 100-w

As per given info,
75% of women (w) are left handed. So, (100-75)% must be right handed i.e. 25%.
Further, number of right handed women = 12
So, 25% of w = 12
Thus, w= 48

Therefore, number of men = 100 -w = 100 - 48 = 52

Answer (B)


shrive555
In a group of 100 adults, 75 percent of the women are left-handed. If there are 12 right-handed women in the group, how many men are in the group?

A. 48
B. 52
C. 54
D. 60
E. 62
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