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In a neighborhood having 90 households, 11 did not have
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23 May 2012, 12:24

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5% (low)

Question Stats:

92% (01:22) correct 8% (01:39) wrong based on 170 sessions

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In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

Re: In a neighborhood having 90 households, 11 did not have
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24 May 2012, 00:40

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navigator123 wrote:

In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

A. 30 B. 35 C. 20 D. 18 E. 10

{Total}={Car}+{Bike}-{Both}+{Neither} --> 90=44+{Bike}-12+11 --> {Bike}=47 --> # those who have bike only is {Bike}-{Both}=47-12=35.

Re: In a neighborhood having 90 households, 11 did not have
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20 Jun 2012, 23:55

N(Car or Bike) = N(Car) + N(Bike) - N(Car + Bike)

N(Car or Bike) = 90-11 = 79

N(Car) = 44

N(Car + Bike) = 12

79 = 44 + N(Bike) - 12

N (Bike) = 47

But this includes people with Bike and Car both.

People with just Bike = 47 - 12 = 35

Pls tell where I am wrong.

navigator123 wrote:

In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

Re: In a neighborhood having 90 households, 11 did not have
[#permalink]

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21 Jun 2012, 01:46

nishantmehra01 wrote:

N(Car or Bike) = N(Car) + N(Bike) - N(Car + Bike)

N(Car or Bike) = 90-11 = 79

N(Car) = 44

N(Car + Bike) = 12

79 = 44 + N(Bike) - 12

N (Bike) = 47

But this includes people with Bike and Car both.

People with just Bike = 47 - 12 = 35

Pls tell where I am wrong.

navigator123 wrote:

In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

A. 30 B. 35 C. 20 D. 18 E. 10

You did nothing wrong: answer B is correct. Though after you got that N(Car or Bike) = 79 and N(Car) = 44, you could directly subtract from the group who has a car or a bike (79) the group who has a car (44) to get the group who has only bike: 79-44=35.

Re: In a neighborhood having 90 households, 11 did not have
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15 Aug 2013, 11:02

Bunuel wrote:

navigator123 wrote:

In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

A. 30 B. 35 C. 20 D. 18 E. 10

{Total}={Car}+{Bike}-{Both}+{Neither} --> 90=44+{Bike}-12+11 --> {Bike}=47 --> # those who have bike only is {Bike}-{Both}=47-12=35.

Answer: B.

Hope it's clear.

Is "11 did not have either a car or a bike" same as "11 did have neither a car nor a bike" ?

In a neighborhood having 90 households, 11 did not have
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08 Sep 2014, 01:20

ParmarKarishma wrote:

Bunuel wrote:

navigator123 wrote:

In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

A. 30 B. 35 C. 20 D. 18 E. 10

{Total}={Car}+{Bike}-{Both}+{Neither} --> 90=44+{Bike}-12+11 --> {Bike}=47 --> # those who have bike only is {Bike}-{Both}=47-12=35.

Answer: B.

Hope it's clear.

Is "11 did not have either a car or a bike" same as "11 did have neither a car nor a bike" ?

yes its same; Please refer the diagram in above post

11 don't have car & bikes (They are out of the vehicles set)
_________________

Re: In a neighborhood having 90 households, 11 did not have
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15 Mar 2017, 16:21

navigator123 wrote:

In a neighborhood having 90 households, 11 did not have either a car or a bike. If 12 households had a both a car and a bike and 44 had a car, how many had bike only?

A. 30 B. 35 C. 20 D. 18 E. 10

We can use the following formula:

# of households = # with a car + # with a bike - # with both + # with neither

90 = 44 + b - 12 + 11

90 = 43 + b

47 = b

We see that 47 households had a bike and 12 of them also had a car; thus, 47 - 12 = 35 households had a bike only.

Answer: B
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