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Sergey_is_cool
Among coordinates A(0,0), B(3,1), C(x,y), what values for (x, y), which are integers, will satisfy AB=AC?

the only way you can have AB=AC if C(x=3, y=-1)


I don't agree.
Imagine a right triangular with the lengths 1 and 3 which are the two smaller sides.
You can habe C(x,y) = 3,1 ; 3,-1; -3,1 ; -3,-1; 1,3; 1,-3; -1,3; -1,-3.

5^(1/2) is not possible because it is not an integer. There are not other integer that can be squared and add up to ten. Only 3 and 1.


Concerning the other question:

I'm a little bit irritated because (1) and (2) give me two different solutions for the problem and I always read that if both statements are correct, the vield the same solution.



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