Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack
GMAT Club

 It is currently 26 Mar 2017, 23:58

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In a set of integers, each term is two more than the

Author Message
Senior Manager
Joined: 19 Feb 2004
Posts: 414
Location: Lungi
Followers: 1

Kudos [?]: 30 [0], given: 0

In a set of integers, each term is two more than the [#permalink]

### Show Tags

19 Feb 2004, 08:47
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a set of integers, each term is two more than the previous term and x, y, and z are the first, middle and last terms, respectively. which of the following equals x^2 + 2xz + z^2
a. 2y
b. 2y^2
c. 4y
d. 4y^2
e. 6y^4
Intern
Joined: 26 Jan 2004
Posts: 35
Location: US
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

19 Feb 2004, 09:07
I am new member here, this is my first attempt. Hope to contribute and learn.

x^2+2xz+z^2 = (x+z)^2 = (x+z)(x+z)
Y is the middle term, so
(x+z) = y-2 + y+2 = 2y
2y.2y = 4y^2

Thanks.
Senior Manager
Joined: 05 Feb 2004
Posts: 290
Location: USA
Followers: 1

Kudos [?]: 5 [0], given: 0

### Show Tags

19 Feb 2004, 09:19
Are they Consecutive integers???
Intern
Joined: 26 Jan 2004
Posts: 35
Location: US
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

19 Feb 2004, 09:29
Since they did not mention how many are there in the series, I assumed smallest possible series namely, 3 (x, y, z). Could be wrong.

-SP
SVP
Joined: 30 Oct 2003
Posts: 1793
Location: NewJersey USA
Followers: 6

Kudos [?]: 100 [0], given: 0

### Show Tags

19 Feb 2004, 09:42
Exactly same procedure as of asagem99
Director
Joined: 03 Jul 2003
Posts: 652
Followers: 3

Kudos [?]: 92 [0], given: 0

### Show Tags

19 Feb 2004, 12:37
Agree with the crowd!
19 Feb 2004, 12:37
Display posts from previous: Sort by