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Bunuel
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55% = 1100
62% = 1240
37%= 740

Only A + Only B = (1100-740) + (1240-740)

860

option D
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Total executives who read newsletter = A+B-AB = 55+62-37 = 80
Therefore, 80% of the total of 2000 executives read newsletter i.e 1600 this includes executives who read both A and B newsletters. We need no. of the executive who read ATMOST 1 newsletter.

Therefore, 1600-(2000*37%) = 860
Additionally, we also have 400 executives who neither read newsletter A nor B

So, 860+400= 1260

Answer: B
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resolved it in the same way as guys above, 860 which for sure makes no sense as we know at least 55% reads A, so 1100 reads newspaper. Missed the clue "at most"

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pushpitkc
P(B) = 62/100∗2000=1240 not 1210
so in your formula 430 should be corrected to 500
then
P(Neither) = 2000 - 360 - 500- 740 = 400
then
P(At most 1) = P(Neither) + P(Only A) + P(Only B) = 500 + 400 + 360 = 1260(Option B)
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I think this is pretty simple, only one calculation required. There are 37% who read both newsletters A and B.

So remaining 63% (of 2000) are those who read either only one newsletter (A or B), or neither. So all those 63% count as 'those who read at most one newsletter'. Thus answer = 63% of 2000 = 1260

Hence B answer
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cbh
resolved it in the same way as guys above, 860 which for sure makes no sense as we know at least 55% reads A, so 1100 reads newspaper. Missed the clue "at most"

P.S.
pushpitkc
P(B) = 62/100∗2000=1240 not 1210
so in your formula 430 should be corrected to 500
then
P(Neither) = 2000 - 360 - 500- 740 = 400
then
P(At most 1) = P(Neither) + P(Only A) + P(Only B) = 500 + 400 + 360 = 1260(Option B)

Thanks a ton for noticing and informing, cbh. Have made the necessary changes!
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Bunuel
In a survey, 2000 executives were each asked whether they read newsletter A or newsletter B. According to the survey, 55 percent of the executives read newsletter A, 62 percent read newsletter B, and 37 percent read both newsletter A and newsletter B. How many of the executives surveyed read at most one among newsletter A and newsletter B?

(A) 1600
(B) 1260
(C) 900
(D) 860
(E) 760

The phrase “at most one” means “one or fewer.” Since 2,000 x 0.37 = 740 executives read both newsletters A and B, there must be 2,000 - 740 = 1,260 executives who read at most one of two newsletters (which means they could read only newsletter A, or only newsletter B, or neither).

Answer: B
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The survey consists of ppl who read 0,1 or 2 papers. Total surveyed: 2000
Total that read 2 papers: 37% x 2000 = 740.
Ppl that read atmost one => Ppl that read <=1 . That is 0 or 1 newspapers.
Total - Both = 2000 - 740 = 1260
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In the Question, it is asked: "executives surveyed read at most one among newsletter A and newsletter B?".

So we are not supposed to add the number of executives who read none (neither A nor B).

So the answer should be the addition of numbers who read only A and who read only B. i.e. 400+360 = 860.

The answer should be 'D'.
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Agree with Nikita. It says at most 1 "among A & B". Hence answer should be 860.

Please explain.
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Ploypailin allice:
1. If the question asks about at most one (including “neither”), the answer is (B) 1260.
2. If the question asks about exactly one (A or B but not both), the answer is (D) 860.
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