Given data :
55 percent of the executives read newsletter A
62 percent read newsletter B
37 percent read both newsletter A and newsletter B
Total = 2000
From the data we can infer
P(A) = \(\frac{55}{100} * 2000 = 1100\)
P(B) = \(\frac{62}{100} * 2000 = 1240\)
P(Both) = \(\frac{37}{100} * 2000 = 740\)
P(Only A) = P(A) - P(Both) = 1100 - 740 = 360
P(Only B) = P(B) - P(Both) = 1240 - 740 = 500
P(Total) = P(Only A) + P(Only B) + P(Both) + P(Neither)
Hence, P(Neither) = P(Total) - {P(Only A) + P(Only B) + P(Both)}
Substituting values,
P(Neither) = 2000 - 360 - 500 - 740 = 400
P(At most 1) = P(Neither) + P(Only A) + P(Only B) = 400 + 500 + 360 =
1260(Option B)
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