Author 
Message 
TAGS:

Hide Tags

Senior Manager
Joined: 23 Oct 2010
Posts: 370
Location: Azerbaijan
Concentration: Finance

In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
01 Oct 2011, 03:40
2
This post received KUDOS
5
This post was BOOKMARKED
Question Stats:
75% (02:37) correct 25% (02:28) wrong based on 212 sessions
HideShow timer Statistics
In a survey of 348 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured? (A) 7/12 (B) 8/41 (C) 9/348 (D) 1/8 (E) 41/91
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Happy are those who dream dreams and are ready to pay the price to make them come true
I am still on all gmat forums. msg me if you want to ask me smth
Last edited by Bunuel on 12 Nov 2014, 09:43, edited 1 time in total.
RENAMED THE TOPIC.



Manager
Joined: 20 Aug 2011
Posts: 137

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
01 Oct 2011, 04:11
let a be the ones who are uninsured, c be those who work parttime and b be those who do both and d be neither. We have to find d/348 Given b+c=104 a+b=54 b=12.5(104)/100=13 so a=41 a+b+c=41+104=145 d=348145=203 d/348=203/348=7/12 or d/348>0.5 so eliminate b, c, d, and e
_________________
Hit kudos if my post helps you. You may send me a PM if you have any doubts about my solution or GMAT problems in general.



Senior Manager
Joined: 23 Oct 2010
Posts: 370
Location: Azerbaijan
Concentration: Finance

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
01 Oct 2011, 04:17
here is my approach
Attachments
Book1.xlsx [8.39 KiB]
Downloaded 134 times
_________________
Happy are those who dream dreams and are ready to pay the price to make them come true
I am still on all gmat forums. msg me if you want to ask me smth



Director
Joined: 01 Feb 2011
Posts: 696

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
01 Oct 2011, 09:15
1
This post was BOOKMARKED
UINUITotal PT(12.5/100)*104 = 13 54 NPT10413 x294 Total104348
we have to find not part time and not uninsured . in other words not part time and insured = x/348 = (294104+13)/348
=203/348 = 7/12
Answer is A.



Manager
Joined: 20 Nov 2010
Posts: 196

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
02 Oct 2011, 09:45



Senior Manager
Status: mba here i come!
Joined: 07 Aug 2011
Posts: 253

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
06 Oct 2011, 07:10
348 = 104+5413+n n (neither) =203 probability = 203/348 = 7/12
_________________
press +1 Kudos to appreciate posts Download Valuable Collection of Percentage Questions (PS/DS)



Director
Status: No dream is too large, no dreamer is too small
Joined: 14 Jul 2010
Posts: 577

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
06 Oct 2011, 09:05



VP
Status: Been a long time guys...
Joined: 03 Feb 2011
Posts: 1359
Location: United States (NY)
Concentration: Finance, Marketing
GPA: 3.75

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
08 Oct 2011, 04:51
2
This post received KUDOS
catfreak wrote: Any shortcuts for reducing 203/348 > 7/12 . Took most of my time. look at the options...only one option is more than 50%...
_________________
Prepositional Phrases ClarifiedElimination of BEING Absolute Phrases Clarified Rules For Posting www.UnivScholarships.com



Manager
Joined: 21 Aug 2010
Posts: 182
Location: United States

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
09 Oct 2011, 21:42
GIVEN part time full time UNI A B 104 INS C X F Tot 54 E F=348104=244 E=34854=294 A=12.5 % of 54 = 13 A+B = 104 B = 91 A+C=54==>C=41 C+X=244===>X=203 part time full time UNI 13 91 104 INS 41 203 244 54 294 Probability ===>203/348 ==>7/12 ans (A)
_________________




Senior Manager
Joined: 13 May 2011
Posts: 287
WE 1: IT 1 Yr
WE 2: Supply Chain 5 Yrs

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
09 Oct 2011, 22:58
Using Van diagram: if: U= #of uninsured P= Part Timer Common area between U and P = X= 13 U and P = 91+13+41= 145 neither U and P = 348145=203 Therefore, Probability = 203/348=7/12



Manager
Joined: 10 Jan 2011
Posts: 207
Location: India
GMAT Date: 07162012
GPA: 3.4
WE: Consulting (Consulting)

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
10 Oct 2011, 06:22
U = 104 (uninsured) P = 54 (part time) u U P = 104*12.5% = 13 (unisured and part time) I = 348104 = 244 (insured) I U F = 244 (5413) = 203 (insured and full time) Probability = 203/348 = 7/12
_________________
Analyze why option A in SC wrong



Intern
Joined: 20 Aug 2012
Posts: 22

In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
13 Nov 2014, 04:58
LalaB wrote: In a survey of 348 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured?
(A) 7/12 (B) 8/41 (C) 9/348 (D) 1/8 (E) 41/91
Attachments
File comment: the person will neither work part time nor be uninsured are 203 Total Number of persons are 348 So the probability will be 203/348 =7/12
SOL.png [ 2.65 KiB  Viewed 3702 times ]



Board of Directors
Joined: 17 Jul 2014
Posts: 2752
Location: United States (IL)
Concentration: Finance, Economics
GPA: 3.92
WE: General Management (Transportation)

In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
25 Mar 2016, 18:35
LalaB wrote: In a survey of 348 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured?
(A) 7/12 (B) 8/41 (C) 9/348 (D) 1/8 (E) 41/91 i went with approximations on this one... insured total = 348  104 = 244 104 uninsured, 1/8 or 13 work part time. so 41 who work part time are insured. or 203 are insured and do not work part time. 203/348 that's way more than 1/2 B, C, D, and E can be eliminated right away. another way to look at this problem: work full time  294 out of this number, a very few are uninsured. since we are asked for those who are insured and those who work part time..it definitely needs to be >50%



Senior Manager
Joined: 17 Jun 2015
Posts: 256
GMAT 1: 540 Q39 V26 GMAT 2: 680 Q46 V37

In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
13 Sep 2016, 18:10
Once we have found out that the probability looks like 203/348, it is better to look at the options. Before that, get an estimate of the ratio( 348 is less than double of 203) that we would be looking for. This would help in narrowing down the options that need to be simplified to look for an answer. (A) 7/12  I kept this for the last. Having checked the wide deviation of the other ratios from the possible correct one, I chose A. (B) 8/41  Denominator is more than 5 times the numerator. In other words, the ratio is more than 1:5. Incorrect (C) 9/348  Denominator is more than 40 times the numerator. In other words, the ratio is more than 1:40. Incorrect (D) 1/8  Denominator is 8 times the numerator. In other words, the ratio is more than 1:5. Incorrect (E) 41/91  Denominator is almost 2 times the numerator. In other words, the ratio is more than 1:2. Incorrect
_________________
Fais de ta vie un rêve et d'un rêve une réalité



NonHuman User
Joined: 09 Sep 2013
Posts: 6532

Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part [#permalink]
Show Tags
02 Mar 2018, 09:13
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources




Re: In a survey of 348 employees, 104 of them are uninsured, 54 work part
[#permalink]
02 Mar 2018, 09:13






