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In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units ...
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06 Feb 2019, 19:58
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In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units, then what is the height of the triangle? A. \(\frac{√3}{2}\) B. 1 C. √3 D. 2 E. 2√3
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Re: In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units ...
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06 Feb 2019, 20:24
EgmatQuantExpert wrote: In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units, then what is the height of the triangle? A. \(\frac{√3}{2}\) B. 1 C. √3 D. 2 E. 2√3 Now two cases.. (I) ∠A is the angle opposite the nonequal side, so other two sides are (18060)/2=60.. so it is 606060 an equilateral triangle (II) ∠A is the angle opposite the equal side, so equal angles are 60 and 60 and third angle is 1806060=60.. so it is 606060 an equilateral triangle again Hence it is an equilateral triangle with side 2.. Height = \(\sqrt{3}\frac{side}{2}=\sqrt{3}\) C
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Re: In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units ...
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06 Feb 2019, 20:57
given two sides are equal and one equal =60 degrees Two situations First situation: when one angle is 60 and other two are equal thus 60+2x = 180 thus x = 60. therefore equilateral triangle Second situation: when two angles equal to 60 and other being x thus 120+x = 180 x= 60 again equilateral triangle
now height of equilateral triangle = \(\sqrt{3}/2*side\) \sqrt{3}/2*2 = \sqrt{3} thus C



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Re: In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units ...
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07 Feb 2019, 07:24
Iscoscales triangle with one angle as 60 will be an equilatrel triangle thus by phythogoras hieght will be root 3
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Re: In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units ...
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08 Feb 2019, 00:07
Solution Given:• An isosceles triangle ABC • ∠A = 60 degrees • BC = 2 units To find:• The height of triangle ABC Approach and Working: We know that ∠A + ∠B + ∠C = 180 degrees • ∠B + ∠C = 180 – 60 = 120 Now, we know in an isosceles triangles two angles must be equal • Case 1: if ∠B = ∠C, then ∠B = ∠C = 60 degrees • Case 2: If ∠A = ∠B or ∠A = ∠C, then all angles are equal to 60 degrees So, we can infer that ABC is an equilateral triangle • Therefore, height of triangle ABC = (\(\frac{√3}{2}\)) * length of any side of ABC = (\(\frac{√3}{2}\)) * 2 = √3 units Hence the correct answer is Option C. Answer: C
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Re: In an isosceles triangle ABC, if ∠A = 60 degrees, and BC = 2 units ...
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08 Feb 2019, 00:07






