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# In each production lot for a certain toy, 25 percent of the

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Manager
Joined: 07 Jul 2003
Posts: 56

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09 Feb 2004, 12:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In each production lot for a certain toy, 25 percent of the toys are red and 75 percent of the toys are blue. Half the toys are size A and half are size B. If 10 out of a lot of 100 toys are red and size A, how many of the toys are blue and size B?

(A) 15 (B) 25 (C) 30
(D) 35 (E) 40

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Director
Joined: 03 Jul 2003
Posts: 651

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09 Feb 2004, 12:58

Assume Total = 100

N(R) = N(R&A) + N(R&B) = 25
N(Bl) = N(Bl&A) + N(Bl&B) = 75
N(A) = N(R&A) + N(Bl&A) =50
N(B) = N(R&B) + N(Bl&B) 50
N(R&A) = 10

Solving these eqn, gives N(Bl&B) = 35.

Where,
N(X) = Number of X
R = red,
Bl =Blue
A = type A
B = type B

Kudos [?]: 106 [0], given: 0

09 Feb 2004, 12:58
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# In each production lot for a certain toy, 25 percent of the

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