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Sol. Number of ways to arrange 4 vowels (I repeating) on 4 even places = 4!/2 = 12
Number of ways to arrange 5 consonants on 5 odd places = 5!= 120
Hence required number of arrangements = 120*12 = 1440
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PRECISION has 9 letters containing 5 consonants (P R C S N) and 4 vowels (E I I O), I being repeated twice

Since we have a restriction that vowels have to occupy even places, we need to satisfy the condition.

The 4 vowels can occupy the 4 even spaces (2nd, 4th, 6th and 8th places) in 4! / 2! = 12 ways

The 5 consonants can occupy the odd places in 5! = 120 ways


Total number of ways = 120 * 12 = 1440


Option D

Arun Kumar


Do you divide by 2! to reflect the repeating letter "I"? Could you kindly elaborate on how to approach such problems in general?

Consider this:
You have to arrange 3 distinct objects: A, B and C
You can do it in 3! ways i.e. 6 ways
ABC, ACB, BAC, BCA, CAB, CBA

What if two are repeated: A, A B
Call them A1 and A2 and arrange in 6 ways again
A1 A2 B, A1 B A2, A2 A1 B, A2 B A1, B A1 A2, B A2 A1

But here is the problem: A1 and A2 are the same. So the similarly colored pairs represent one arrangement only.
Hence we divide 6 by 2.
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