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=>

There are four ways (girls) to fill the first position and three ways (girls left over) to fill the last position. The remaining five positions can be filled by the five remaining children (three boys and two girls) in 5!=120 ways.

By the multiplication rule, there are 4 * 3 * 120 = 1,440 different lines possible.

Therefore, the answer is D.

Answer: D
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In how many ways can three boys and four girls line up in a row, if girls take the first and last positions?

__ __ __ __ __ __ __

G G

No. of ways girls can take the first and last positions = 4C2=6
No. of ways of arrangement of the above = 6x2! = 12
No. of ways of arrangement of other positions = 5! = 120

Total No. of ways = 120x12=1440

Hence D
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