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25 Oct 2024, 01:30
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D
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Difficulty:
65%
(hard)
Question Stats:
65% (02:51) correct
35%
(02:41)
wrong
based on 135
sessions
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In order for a nursery to meet the conditions of its insurance there must be at least one adult present for every 4 children. The total number of children and adults at the nursery is 24. Is the nursery meeting the terms of its insurance?
(1) The difference between the number of children and the number of adults is smaller than 15
(2) If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3
(1) The difference between the number of children and the number of adults is smaller than 15
(2) If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3
25 Oct 2024, 05:16
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\(Adults+Children=a+c=24\)
Required ratio of Children to Adults \(= \frac{c}{a}=\frac{4}{1}=4\)
To meet insurance terms, the ratio should be \(\frac{c}{a}<4\)
is \(\frac{c}{a}<4?\)
Statement 1: The difference between the number of children and the number of adults is smaller than 15
\(c-a<15\).
For minimum number of adults, \(c-a=14\)
We have two equations, \(c-a=14\) & \(c+a=24\)
\(c=19, a=5\)
\(\frac{c}{a}=\frac{19}{5}=3.8\)
Sufficient
Statement 2: If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3
\(\frac{a+1}{c-1}=\frac{1}{3}\)
\(3a+3=c-1\)
\(c-3a=4\)
\(c+a=24\)
Sufficient
Answer: D
Required ratio of Children to Adults \(= \frac{c}{a}=\frac{4}{1}=4\)
To meet insurance terms, the ratio should be \(\frac{c}{a}<4\)
is \(\frac{c}{a}<4?\)
Statement 1: The difference between the number of children and the number of adults is smaller than 15
\(c-a<15\).
For minimum number of adults, \(c-a=14\)
We have two equations, \(c-a=14\) & \(c+a=24\)
\(c=19, a=5\)
\(\frac{c}{a}=\frac{19}{5}=3.8\)
Sufficient
Statement 2: If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3
\(\frac{a+1}{c-1}=\frac{1}{3}\)
\(3a+3=c-1\)
\(c-3a=4\)
\(c+a=24\)
Sufficient
Answer: D
25 Oct 2024, 09:08
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diff
tgsankar10
\(Adults+Children=a+c=24\)
Required ratio of Children to Adults \(= \frac{c}{a}=\frac{4}{1}=4\)
To meet insurance terms, the ratio should be \(\frac{c}{a}<4\)
is \(\frac{c}{a}<4?\)
Statement 1: The difference between the number of children and the number of adults is smaller than 15
\(c-a<15\).
For minimum number of adults, \(c-a=14\)
We have two equations, \(c-a=14\) & \(c+a=24\)
\(c=19, a=5\)
\(\frac{c}{a}=\frac{19}{5}=3.8\)
Sufficient
Statement 2: If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3
\(\frac{a+1}{c-1}=\frac{1}{3}\)
\(3a+3=c-1\)
\(c-3a=4\)
\(c+a=24\)
Sufficient
Answer: D
if difference is given then wouldn't be it like |C-A| <15 Required ratio of Children to Adults \(= \frac{c}{a}=\frac{4}{1}=4\)
To meet insurance terms, the ratio should be \(\frac{c}{a}<4\)
is \(\frac{c}{a}<4?\)
Statement 1: The difference between the number of children and the number of adults is smaller than 15
\(c-a<15\).
For minimum number of adults, \(c-a=14\)
We have two equations, \(c-a=14\) & \(c+a=24\)
\(c=19, a=5\)
\(\frac{c}{a}=\frac{19}{5}=3.8\)
Sufficient
Statement 2: If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3
\(\frac{a+1}{c-1}=\frac{1}{3}\)
\(3a+3=c-1\)
\(c-3a=4\)
\(c+a=24\)
Sufficient
Answer: D
