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In order to complete a reading assignment on time, Terry

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Joined: 12 Jun 2016
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Concentration: Technology, Leadership
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Re: In order to complete a reading assignment on time, Terry [#permalink]

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New post 24 Jul 2017, 08:17
Can we think of it in this way? Please correct me if I am wrong.

Last 6 days Terry has to read 690 pages in 6 days. Meaning he has to Average 115 pages per day. His intended average was 90. So, he has to "gain" 115-90 = 25 pages per day to catch up on his intended average. In total he has to gain 25*6 = 150 pages.

If he has to gain 150 pages, it means he has lost 150 pages initially. His initial loss per day = 90-75 = 15. Hence to lose a total of 150 pages - he would have studied at this rate for 150/15 = 10 days.

Total time = 10 days (with a loss of 15 pages per day over intended average ) + 6 days (with a gain of 25 pages per day over intended average) = 16.
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Re: In order to complete a reading assignment on time, Terry [#permalink]

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New post 09 Aug 2017, 18:55
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There is really one variable in this question: other unknowns can be derived from the number of days in total Terry has to complete the reading assignment. So let x be that number of days. We have:

90x = Total number of pages = 75(x-6) + 690
So 15x = 240
x = 16

QED.
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Re: In order to complete a reading assignment on time, Terry [#permalink]

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New post 09 Aug 2017, 19:06
Please correct me if I am wrong,

My thinking is
She has 690 pages left for the last 6 days
She supposed to 540 pages left (since she planned to read 90 pages per day)

690-540= 160 pages behind)

She had been reading 75 pages per day, (90-75= 15 behind every day)
160/15= 10~ days at the beginning
10~days+ the last 6 days = 16

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Re: In order to complete a reading assignment on time, Terry   [#permalink] 09 Aug 2017, 19:06

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In order to complete a reading assignment on time, Terry

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