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In the coordinate plane, line Q has x-intercept 2 and y-intercept -1.

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In the coordinate plane, line Q has x-intercept 2 and y-intercept -1.  [#permalink]

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New post Updated on: 12 Jan 2019, 07:33
1
2
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

77% (01:52) correct 23% (02:31) wrong based on 48 sessions

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In the coordinate plane, line Q has x-intercept 2 and y-intercept -1. If points (1, y) and (x, 0) lie on the line, what is the value of x + y?

A. -2
B. -1
C. 0
D. 1
E. 1.5

Source: Experts Global GMAT
Difficulty Level: 600

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Originally posted by SajjadAhmad on 12 Oct 2018, 10:43.
Last edited by SajjadAhmad on 12 Jan 2019, 07:33, edited 2 times in total.
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Re: In the coordinate plane, line Q has x-intercept 2 and y-intercept -1.  [#permalink]

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New post 12 Oct 2018, 10:54
OA-E.
Eqn of the line=>y=1/2x-1.
As (1,y) and (x,0) lies here,the eqn will be satisfied by both these points.
Solving we get=>x=2,y=-1/2.
2+(-1/2)=3/2=1.5
Ans E
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Re: In the coordinate plane, line Q has x-intercept 2 and y-intercept -1.  [#permalink]

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New post 12 Oct 2018, 11:09
1
SajjadAhmad wrote:
In the coordinate plane, line Q has x-intercept 2 and y-intercept -1. If points (1, y) and (x, 0) lie on the line, what is the value of x + y?

A. -2
B. -1
C. 0
D. 1
E. 1.5

EG-8


y-intercept is when x = 0
x-intercept is when y = 0

y = mx + b

-1 = 0 + b so b = -1

0 = 2m - 1 so m = 1/2

Now substitute (x,0) to find the value of x

0 = 1/2x - 1
x = 2

Subtitute (1,y) to find the value of y

y = 1/2 - 1 = -1/2

x + y = 2 - 1/2 = 1.5

Answer choice E

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Re: In the coordinate plane, line Q has x-intercept 2 and y-intercept -1.  [#permalink]

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New post 13 Oct 2018, 04:40
1
\(y=mx+c\)
\(m=\frac{y2-y1}{x2-x1}\)
\(=\frac{-1-0}{0-2}\)
\(=\frac{1}{2}\)

\(y=mx+c\)
\(y=\frac{1}{2}(1)-1\)
\(y=-0.5\)

\(y=mx+c\)
\(0=\frac{1}{2}(x)-1\)
\(x=2\)

\(x+y=2-0.5=1.5\)

Answer is E.
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Re: In the coordinate plane, line Q has x-intercept 2 and y-intercept -1.   [#permalink] 13 Oct 2018, 04:40
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