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In the coordinate plane, what is the distance between points (3, 5) an
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21 Feb 2016, 09:12
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Re: In the coordinate plane, what is the distance between points (3, 5) an
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21 Feb 2016, 10:43
Distance between (3, 5) and (7, 10) = [ (73)^2 + (105)^2 ]^(1/2) = [ 4^2 + 5^2 ]^(1/2) = [41]^(1/2) Answer E
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Re: In the coordinate plane, what is the distance between points (3, 5) an
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21 Feb 2016, 21:26
Distance between 2 points is [(x2x1)^2 +(y2y1)^2]^1/2
= [ (73)^2 + (105)^2 ]^(1/2) = [ 4^2 + 5^2 ]^(1/2) = [41]^(1/2)
Thus answer is E



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Re: In the coordinate plane, what is the distance between points (3, 5) an
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22 Feb 2016, 00:01
sqrt((y2y1)^2 +(x2x1)^2) thus sqrt((105)^2+(73)^2) sqrt(25+16)= sqrt(41)
Ans: E



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Re: In the coordinate plane, what is the distance between points (3, 5) an
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22 Feb 2016, 15:01
Bunuel wrote: In the coordinate plane, what is the distance between points (3, 5) and (7, 10)?
A. 3 B. 4 C. \(2\sqrt{5}\) D. \(\sqrt{37}\) E. \(\sqrt{41}\)
Related ResourcesThe following free video covers the concepts/strategies that are useful for answering this question: Cheers, Brent
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In the coordinate plane, what is the distance between points (3, 5) an
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23 Feb 2016, 01:41
Bunuel wrote: In the coordinate plane, what is the distance between points (3, 5) and (7, 10)?
A. 3 B. 4 C. \(2\sqrt{5}\) D. \(\sqrt{37}\) E. \(\sqrt{41}\)
Kudos for correct solution. Distance between two points = \(\sqrt{((x2  x1)^2 + (y2  y1)^2)}\) In this particular case, \(\sqrt{((73)^2 + (10  5)^2 )}\)=\(\sqrt{(16 + 25)}\) = \(\sqrt{41}\) Option E



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Re: In the coordinate plane, what is the distance between points (3, 5) an
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14 Jul 2016, 07:05
Bunuel wrote: In the coordinate plane, what is the distance between points (3, 5) and (7, 10)?
A. 3 B. 4 C. \(2\sqrt{5}\) D. \(\sqrt{37}\) E. \(\sqrt{41}\)
Kudos for correct solution. Use distance formula \(d=\sqrt{(delta x)^2 +(delta y)^2}\) \(d=\sqrt{(73)^2 +(105)^2}\) \(d=\sqrt{(4)^2 +(5)^2}\) \(d=\sqrt{(16)+(25)}\) \(d=\sqrt{41}\) Answer is E
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In the coordinate plane, what is the distance between points (3, 5) an
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06 Nov 2017, 08:43
Bunuel wrote: In the coordinate plane, what is the distance between points (3, 5) and (7, 10)?
A. 3 B. 4 C. \(2\sqrt{5}\) D. \(\sqrt{37}\) E. \(\sqrt{41}\)
Kudos for correct solution. Approach: One step away from the distance formula. For me, the latter is slower. This method = half a minute. Find the leg lengths of the right triangle created by the two points (easy to see if you sketch). Hypotenuse = distance between points. The length of one leg of the right triangle is the difference between the xcoordinates: (73) = 4 The length of the other leg is the difference between the ycoordinates: (105) = 5 Pythagorean theorem: (leg 1)\(^2\) + (leg 2)\(^2\) = hypotenuse\(^2\) (= d\(^2\)) 4\(^2\) + 5\(^2\) = d\(^2\) 16 + 25 = d\(^2\) d\(^2\) = 41 d = \(\sqrt{41}\)Answer E



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Re: In the coordinate plane, what is the distance between points (3, 5) an
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08 Nov 2017, 16:29
Bunuel wrote: In the coordinate plane, what is the distance between points (3, 5) and (7, 10)?
A. 3 B. 4 C. \(2\sqrt{5}\) D. \(\sqrt{37}\) E. \(\sqrt{41}\) We can use the distance formula: d = √[(y2  y1)^2 + (x2  x1)^2] d = √[(10  5)^2 + (7  3)^2] d = √(5^2 + 4^2) d = √(25 + 16) = √41 Answer: E
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