In the figure, ABCD is a square, and OB is a radius of the circle. Is BC a tangent to the circle?If BC is tangent to the circle, it must be perpendicular to radius OB, making triangle BOC a right triangle.
(1) PC = 2. This implies that OC = radius + PC = 5. So, we know the lengths of the two sides in triangle BOC: OC = 5 and OB = 3. BOC could be 3-4-5 right triangle, but it might as well not be, for example it could be 3-5-5 triangle. Not sufficient.
(2) Area of the square is 16 --> BC = 4. The same here. Not sufficient.
(1)+(2) We know the lengths of all sides in triangle BOC: OC = 5, BC = 4 and OB = 3. So, BOC is a right triangle. Sufficient.
Answer: C.
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