Bunuel wrote:

In the figure above, A and B are the centers of the two circles. If each circle has area 10, what is the area of the rectangle?

(A) 20

(B) 20 – 10/π

(C) 40/π

(D) 50/π

(E) 60/π

Attachment:

2017-11-15_1036_001.png

Since the area of the circle is 10,

π*r^2 = 10

r = \(\sqrt{10/π}\)

The breadth of the rectangle is the diameter of either circle which is \(2\sqrt{10/π}\)

Similarly, the length of the rectangle will be equal to \(3\sqrt{10/π}\)

Hence, the area of the rectangle will be \((2\sqrt{10/π})\)*\((3\sqrt{10/π})\) = 60/π(Option E)

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