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Tough and Tricky questions: Geometry.

In the figure above, a circle with center O is inscribed in the square WXYZ. The segment XZ has a length of 3√2 inches. What is the radius of the circle in inches?

Re: In the figure above, a circle with center O is inscribed in the square [#permalink]

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26 Dec 2014, 10:02

The diagonale of the square has a length of \(3\sqrt{2}\) inches. Therefore, one side of the square has the length 3 inches. Since the circle in inscribed in the square, the radius must be one half the length of the square's side: 1.5 inches.

Answer B.
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\(\sqrt{-1}\) \(2^3\) \(\Sigma\) \(\pi\) ... and it was delicious!

Re: In the figure above, a circle with center O is inscribed in the square [#permalink]

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26 Dec 2014, 17:26

Bunuel wrote:

Tough and Tricky questions: Geometry.

In the figure above, a circle with center O is inscribed in the square WXYZ. The segment XZ has a length of 3√2 inches. What is the radius of the circle in inches?

Re: In the figure above, a circle with center O is inscribed in the square [#permalink]

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27 Dec 2014, 01:08

Since the diagnol of square is 3 sqrt. 2 . The side of the square will be 3 each. We as sqaure diagnol:side=x*sqrt2. where x is the side of the square.

You can verify the same through pythagoreas theorem.

Now Side of the square is diameter of the circle. hence diameter is 3. Thus radius is 1.5. Thus answer is B.

In the figure above, a circle with center O is inscribed in the square WXYZ. The segment XZ has a length of 3√2 inches. What is the radius of the circle in inches?

Triangle XYZ is an isosceles right triangle. The length of each leg is 3. Since the diameter of the circle is equal to the height of the square, the diameter is equal to 3. So the radius is equal to 1.5 inches.

Alternatively, since the sides XY and ZY are equal, set them equal to x. Then 2x² = (3√2)² by the Pythagorean Theorem. Solving for x: x² = 9 and so x = 3. Since x represents the side of the square or the diameter of the circle, we divide by 2 to get the radius. So, the radius must be 1.5.

Re: In the figure above, a circle with center O is inscribed in the square [#permalink]

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27 Mar 2017, 10:17

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Re: In the figure above, a circle with center O is inscribed in the square [#permalink]

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30 Jul 2017, 20:01

Sorry i have question here. why is the side of the square the diameter of the circle? Also the diagonal of the square is the diameter of the circle right?

Sorry i have question here. why is the side of the square the diameter of the circle? Also the diagonal of the square is the diameter of the circle right?

If a circle is inscribed in a square, the diameter of the circle will be equal to the side of the square. Check the image below:

Re: In the figure above, a circle with center O is inscribed in the square [#permalink]

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01 Aug 2017, 00:58

Bunuel wrote:

Tough and Tricky questions: Geometry.

In the figure above, a circle with center O is inscribed in the square WXYZ. The segment XZ has a length of 3√2 inches. What is the radius of the circle in inches?

As the given figure is a square. Triangles XZW and XYZ are isoceles right triangles, which is a 45-45-90 triangle. The ratio of the sides of this kind of triangle is 1: 1: \(\sqrt{2}\). Given that the diagonal, which is hypotenuse for both the triangles, is 3 \(\sqrt{2}\) Therefore, the sides of the square= 3 When circle is inscribed in a square, diameter of the circle = sides of the square (= 3 here). Thus, radius= 3/2= 1.5 Answer: B
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In the figure above, a circle with center O is inscribed in the square WXYZ. The segment XZ has a length of 3√2 inches. What is the radius of the circle in inches?

A. 1 B. 1.5 C. 2 D. 2.5 E. 3

We see that 3√2 = the diagonal of the square; thus:

3√2 = side√2

3 = side of square

Since the side of the square also equals the diameter of the circle, the radius of the circle is 1.5.

Answer: B
_________________

Jeffery Miller Head of GMAT Instruction

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