GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 18 Feb 2020, 22:56

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In the figure above, if the area of the larger square region is twice

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 61283
In the figure above, if the area of the larger square region is twice  [#permalink]

### Show Tags

27 Feb 2019, 23:24
00:00

Difficulty:

45% (medium)

Question Stats:

77% (02:05) correct 23% (01:30) wrong based on 25 sessions

### HideShow timer Statistics

In the figure above, if the area of the larger square region is twice the area of the smaller square region, and if a diagonal of the smaller square has a length of 1 foot, then a side of the larger square is how many feet longer than a side of the smaller square?

A. $$\frac{2 - \sqrt{2}}{2}$$

B. $$\sqrt{2}-1$$

C. 1

D. $$\sqrt{2}$$

E. 2

Attachment:

2019-02-28_1121.png [ 2.83 KiB | Viewed 394 times ]

_________________
Manager
Joined: 17 May 2018
Posts: 140
Location: India
Re: In the figure above, if the area of the larger square region is twice  [#permalink]

### Show Tags

28 Feb 2019, 00:22
1
Hi Bunuel the figure is missing. Could you please check it. Thank you

Posted from my mobile device
Math Expert
Joined: 02 Sep 2009
Posts: 61283
Re: In the figure above, if the area of the larger square region is twice  [#permalink]

### Show Tags

28 Feb 2019, 00:26
1
sumi747 wrote:
Hi Bunuel the figure is missing. Could you please check it. Thank you

Posted from my mobile device

_______________________
Fixed that. Thank you.
_________________
Manager
Joined: 31 Dec 2018
Posts: 114
Location: India
Re: In the figure above, if the area of the larger square region is twice  [#permalink]

### Show Tags

28 Feb 2019, 00:43
Steps:
1.Side of the smaller square= sqrt(1/2)
2.Area of the larger square = 2*1/2=1
3.Side of the larger square = 1
4.Difference between the sides = 1-sqrt(1/2) = {sqrt(2)-1}/sqrt(2)
5.Multiple by sqrt(2)
6. Option A
Manager
Joined: 17 May 2018
Posts: 140
Location: India
Re: In the figure above, if the area of the larger square region is twice  [#permalink]

### Show Tags

28 Feb 2019, 00:46
1
By property of 45-90-45 triangle we get the sides of small triangle= 1/√2
Hence area of small sqr=1/2
Ar of large sqr= 2*1/2=1
Side of large sqr=1
Therefore difference in length of sides for large and small sqr= 1-1/√2 = (√2-1)/√2= √2*(√2-1)/√2*√2= (2-√2)/2
IMO A

Posted from my mobile device
Attachments

IMG_20190228_141553.jpg [ 4.65 MiB | Viewed 331 times ]

Re: In the figure above, if the area of the larger square region is twice   [#permalink] 28 Feb 2019, 00:46
Display posts from previous: Sort by