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In the figure above, the area of ∆ ABC is

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V
Joined: 02 Sep 2009
Posts: 47080
In the figure above, the area of ∆ ABC is [#permalink]

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New post 15 Dec 2017, 02:03
1
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

89% (00:32) correct 11% (00:47) wrong based on 54 sessions

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P
Joined: 22 Aug 2013
Posts: 1280
Location: India
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Re: In the figure above, the area of ∆ ABC is [#permalink]

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New post 07 Jan 2018, 08:14
Bunuel wrote:
Image
In the figure above, the area of ∆ ABC is

(A) 15
(B) 20
(C) 24
(D) 30
(E) 48

Attachment:
2017-12-15_1258.png


As we can see, ABC is a right angled triangle, with AB and BC as the two legs. Area will be = 1/2 * AB * BC

Now AB and BC can be calculated by counting the squares (as side of each square is one unit only). So AB = 6 units and BC = 8 units. Thus area = 1/2 * 6 * 8 = 24 square units.

Hence C answer
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Joined: 23 Oct 2017
Posts: 64
Re: In the figure above, the area of ∆ ABC is [#permalink]

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New post 07 Jan 2018, 08:32
Bunuel wrote:
Image
In the figure above, the area of ∆ ABC is

(A) 15
(B) 20
(C) 24
(D) 30
(E) 48

Attachment:
2017-12-15_1258.png



-----------------
Simply its applying the formula for calculating area of triangle = (1/2)*base*height , but be careful of the on how the meaurement you are taking from
height = 3-(-3) =6
base = 5-(-3) =8
Area = (1/2) * 6 * 8 =24
Re: In the figure above, the area of ∆ ABC is   [#permalink] 07 Jan 2018, 08:32
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In the figure above, the area of ∆ ABC is

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