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In the figure above, the ratio w/x is 1/3. What is the ratio of (area

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In the figure above, the ratio w/x is 1/3. What is the ratio of (area  [#permalink]

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18 Feb 2018, 21:51
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Difficulty:

25% (medium)

Question Stats:

80% (01:26) correct 20% (01:09) wrong based on 73 sessions

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In the figure above, the ratio w/x is 1/3. What is the ratio of (area ABC)/(area ACD) ?

(A) 1/6
(B) 1/3
(C) 3/1
(D) 6/1
(E) 9/1

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2018-02-19_0948.png [ 11.51 KiB | Viewed 568 times ]

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In the figure above, the ratio w/x is 1/3. What is the ratio of (area  [#permalink]

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18 Feb 2018, 21:57

Given information:
x=3w.
Since, the triangles have the same height, and the area of the triangle is $$\frac{1}{2}$$*base*height

Area of ABC = $$\frac{1}{2}*w*h$$
Area of ACD = $$\frac{1}{2}*3w*h$$

Therefore, the ratio of the areas of triangle ABC to the area of triangle ADC is 1:3(Option B)
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Joined: 05 Jun 2014
Posts: 9
Re: In the figure above, the ratio w/x is 1/3. What is the ratio of (area  [#permalink]

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20 Feb 2018, 10:15
Since both the triangles have the same height, the ratio of their areas should be equal to the ratio of their bases.
Hence, the ratio of the areas would be equal to w/x =1/3

Option B
Re: In the figure above, the ratio w/x is 1/3. What is the ratio of (area &nbs [#permalink] 20 Feb 2018, 10:15
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