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In the figure above, the ratio w/x is 1/3. What is the ratio of (area

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In the figure above, the ratio w/x is 1/3. What is the ratio of (area  [#permalink]

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New post 18 Feb 2018, 22:51
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

78% (01:27) correct 22% (01:08) wrong based on 75 sessions

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In the figure above, the ratio w/x is 1/3. What is the ratio of (area  [#permalink]

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New post 18 Feb 2018, 22:57
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Given information:
x=3w.
Since, the triangles have the same height, and the area of the triangle is \(\frac{1}{2}\)*base*height

Area of ABC = \(\frac{1}{2}*w*h\)
Area of ACD = \(\frac{1}{2}*3w*h\)

Therefore, the ratio of the areas of triangle ABC to the area of triangle ADC is 1:3(Option B)
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Re: In the figure above, the ratio w/x is 1/3. What is the ratio of (area  [#permalink]

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New post 20 Feb 2018, 11:15
Since both the triangles have the same height, the ratio of their areas should be equal to the ratio of their bases.
Hence, the ratio of the areas would be equal to w/x =1/3

Option B
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Re: In the figure above, the ratio w/x is 1/3. What is the ratio of (area   [#permalink] 20 Feb 2018, 11:15
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In the figure above, the ratio w/x is 1/3. What is the ratio of (area

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