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In the figure above, two security lights, L1 and L2, are loc

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In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post Updated on: 25 Aug 2013, 22:24
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In the figure above, two security lights, L1 and L2, are located 100 feet apart. Each illuminates an area of radius 100 feet, and both are located 60 feet from a chain-link fence. What is the total length s of fence, in feet, illuminated by the two lights?

(A) 260
(B) 240
(C) 220
(D) 200
(E) 180

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Asif vai.....


Originally posted by Asifpirlo on 25 Aug 2013, 16:57.
Last edited by Bunuel on 25 Aug 2013, 22:24, edited 1 time in total.
Edited the question.
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Re: In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post 25 Aug 2013, 21:22
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1
Consider S = AB+BC+CD+DE

And, we also know

AB=BC=DE = SQRT(100^2-60^2) = 80

Hence S = 3*(80)+CD

Since CD is definitely >0, from the answer choices we could safely choose option .
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Re: In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post 26 Aug 2013, 00:17
Smallwonder wrote:
Consider S = AB+BC+CD+DE

And, we also know

AB=BC=DE = SQRT(100^2-60^2) = 80

Hence S = 3*(80)+CD

Since CD is definitely >0, from the answer choices we could safely choose option .


Very nice solution my friend..... :)
A good post always worth a kudos. Thus you got one for this
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Re: In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post 11 Sep 2013, 23:04
i don't think this is 700+ sum. It was very easy. Would have been tought if options were like 260,265,270.
In that case you have to calculate CD. Can we do it?
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Re: In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post 14 Sep 2013, 06:54
b2bt wrote:
i don't think this is 700+ sum. It was very easy. Would have been tought if options were like 260,265,270.
In that case you have to calculate CD. Can we do it?


hi b2bt,

yes you can ,, it is alread given that the distance between lights is 100m so CD=100-80=20
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Re: In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post 14 Sep 2013, 08:16
total distance= AB+DE+L1L2
AB=DE=80
L1L2 = 100
Hence total = 80*2+100 = 260.
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Re: In the figure above, two security lights, L1 and L2, are loc  [#permalink]

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New post 21 Apr 2018, 04:35
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: In the figure above, two security lights, L1 and L2, are loc &nbs [#permalink] 21 Apr 2018, 04:35
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