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In the figure above, x =

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V
Joined: 02 Sep 2009
Posts: 42529

Kudos [?]: 135163 [0], given: 12664

In the figure above, x = [#permalink]

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New post 11 Oct 2017, 00:44
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

93% (00:37) correct 7% (02:23) wrong based on 27 sessions

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In the figure above, x =

(A) 75
(B) 90
(C) 100
(D) 105
(E) 150

[Reveal] Spoiler:
Attachment:
2017-10-11_1126_001.png
2017-10-11_1126_001.png [ 5.77 KiB | Viewed 570 times ]
[Reveal] Spoiler: OA

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Kudos [?]: 135163 [0], given: 12664

Manager
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S
Joined: 05 Dec 2016
Posts: 248

Kudos [?]: 26 [0], given: 49

Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
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Re: In the figure above, x = [#permalink]

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New post 11 Oct 2017, 00:59
x = 45 + (bottom leg of side triangle * 2)
Using Pythagorean formula we can find:
bottom leg of side triangle= (50^2-40^2)^1/2=30
x=45+30+30=105

Answer D

Kudos [?]: 26 [0], given: 49

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B
Joined: 22 May 2017
Posts: 90

Kudos [?]: 7 [0], given: 222

GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27
Re: In the figure above, x = [#permalink]

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New post 12 Oct 2017, 04:39
Alexey1989x wrote:
x = 45 + (bottom leg of side triangle * 2)
Using Pythagorean formula we can find:
bottom leg of side triangle= (50^2-40^2)^1/2=30
x=45+30+30=105

Answer D



side of two parallelogram should be 45 plus plus 45 .
So answer can be 90
option B

Kudos [?]: 7 [0], given: 222

Manager
Manager
User avatar
S
Joined: 05 Dec 2016
Posts: 248

Kudos [?]: 26 [0], given: 49

Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
GMAT ToolKit User
Re: In the figure above, x = [#permalink]

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New post 12 Oct 2017, 05:01
Adityagmatclub wrote:
Alexey1989x wrote:
x = 45 + (bottom leg of side triangle * 2)
Using Pythagorean formula we can find:
bottom leg of side triangle= (50^2-40^2)^1/2=30
x=45+30+30=105

Answer D



side of two parallelogram should be 45 plus plus 45 .
So answer can be 90
option B


Sorry, I do not understand your logic.
Could you please specify your line of reasoning.

Kudos [?]: 26 [0], given: 49

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Joined: 22 May 2017
Posts: 90

Kudos [?]: 7 [0], given: 222

GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27
Re: In the figure above, x = [#permalink]

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New post 12 Oct 2017, 05:19
Yes, i was wrong but i can't understand which triangle you are considering for Pythagoras theorem.

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Kudos [?]: 7 [0], given: 222

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Manager
Manager
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S
Joined: 05 Dec 2016
Posts: 248

Kudos [?]: 26 [1], given: 49

Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
GMAT ToolKit User
Re: In the figure above, x = [#permalink]

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New post 12 Oct 2017, 05:28
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Adityagmatclub wrote:
Yes, i was wrong but i can't understand which triangle you are considering for Pythagoras theorem.

Sent from my Redmi Note 3 using GMAT Club Forum mobile app


Look at the picture in attachment, I've applied Pyth formula to find AF and ED.
Attachments

IMG_3315.jpg
IMG_3315.jpg [ 309.61 KiB | Viewed 367 times ]

Kudos [?]: 26 [1], given: 49

Manager
Manager
User avatar
B
Joined: 22 May 2017
Posts: 90

Kudos [?]: 7 [0], given: 222

GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27
Re: In the figure above, x = [#permalink]

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New post 12 Oct 2017, 06:22
Yes, easy problem.

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Kudos [?]: 7 [0], given: 222

Re: In the figure above, x =   [#permalink] 12 Oct 2017, 06:22
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