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# In the figure above, x =

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Math Expert
Joined: 02 Sep 2009
Posts: 50771
In the figure above, x =  [#permalink]

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10 Oct 2017, 23:44
00:00

Difficulty:

(N/A)

Question Stats:

80% (01:07) correct 20% (01:57) wrong based on 47 sessions

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In the figure above, x =

(A) 75
(B) 90
(C) 100
(D) 105
(E) 150

Attachment:

2017-10-11_1126_001.png [ 5.77 KiB | Viewed 867 times ]

_________________
Manager
Joined: 05 Dec 2016
Posts: 244
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: In the figure above, x =  [#permalink]

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10 Oct 2017, 23:59
x = 45 + (bottom leg of side triangle * 2)
Using Pythagorean formula we can find:
bottom leg of side triangle= (50^2-40^2)^1/2=30
x=45+30+30=105

Manager
Joined: 22 May 2017
Posts: 88
GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27
Re: In the figure above, x =  [#permalink]

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12 Oct 2017, 03:39
Alexey1989x wrote:
x = 45 + (bottom leg of side triangle * 2)
Using Pythagorean formula we can find:
bottom leg of side triangle= (50^2-40^2)^1/2=30
x=45+30+30=105

side of two parallelogram should be 45 plus plus 45 .
option B
Manager
Joined: 05 Dec 2016
Posts: 244
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: In the figure above, x =  [#permalink]

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12 Oct 2017, 04:01
Alexey1989x wrote:
x = 45 + (bottom leg of side triangle * 2)
Using Pythagorean formula we can find:
bottom leg of side triangle= (50^2-40^2)^1/2=30
x=45+30+30=105

side of two parallelogram should be 45 plus plus 45 .
option B

Sorry, I do not understand your logic.
Manager
Joined: 22 May 2017
Posts: 88
GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27
Re: In the figure above, x =  [#permalink]

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12 Oct 2017, 04:19
Yes, i was wrong but i can't understand which triangle you are considering for Pythagoras theorem.

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Manager
Joined: 05 Dec 2016
Posts: 244
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: In the figure above, x =  [#permalink]

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12 Oct 2017, 04:28
1
Yes, i was wrong but i can't understand which triangle you are considering for Pythagoras theorem.

Sent from my Redmi Note 3 using GMAT Club Forum mobile app

Look at the picture in attachment, I've applied Pyth formula to find AF and ED.
Attachments

IMG_3315.jpg [ 309.61 KiB | Viewed 652 times ]

Manager
Joined: 22 May 2017
Posts: 88
GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27
Re: In the figure above, x =  [#permalink]

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12 Oct 2017, 05:22
Yes, easy problem.

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Re: In the figure above, x = &nbs [#permalink] 12 Oct 2017, 05:22
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