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# In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB ||

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Math Expert
Joined: 02 Sep 2009
Posts: 43891
In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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20 Mar 2015, 06:13
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In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || CD, what is the value of x? Note: Figure not drawn to scale

A. 75
B. 85
C. 95
D. 105
E. 115

Kudos for a correct solution.
[Reveal] Spoiler: OA

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Joined: 02 Mar 2012
Posts: 356
Schools: Schulich '16
Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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20 Mar 2015, 11:31
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its A =75

angle AED=65 (AED is 180) =angle FEC( opp)

thru above FCE =75 which makes ECB=115 again

EAB =65(vertically opp angles thru thr trnsversal between the parallel lines)
now we have all four angles of quad ABCE

so we can solve x=75
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Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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20 Mar 2015, 19:35
Bunuel wrote:
Attachment:
originals (1).jpg
In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || CD, what is the value of x? Note: Figure not drawn to scale

A. 75
B. 85
C. 95
D. 105
E. 115

Kudos for a correct solution.

It looks to me that triangles ABF and ECF are similar triangles.
If that is the case then angle AED is 65 (found by 180-55-60=65)
Angle CEF is a vertical angle so it also equals 65.
Finally this leads us to angle ECF which is 75 (found by 180-65-40=75)

x= 75

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figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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22 Mar 2015, 23:29

Refer diagram below:

Attachment:

originals%20(1).jpg [ 20.85 KiB | Viewed 2360 times ]

$$\angle ABC = \angle ECF = x$$ (They are alternate angles)

x = 180-(75+40) = 75
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Math Expert
Joined: 02 Sep 2009
Posts: 43891
Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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23 Mar 2015, 04:43
Bunuel wrote:

In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || CD, what is the value of x? Note: Figure not drawn to scale

A. 75
B. 85
C. 95
D. 105
E. 115

Kudos for a correct solution.

MAGOOSH OFFICIAL SOLUTION:
Attachment:

parallellines_text.PNG [ 12.61 KiB | Viewed 2323 times ]

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Joined: 06 Mar 2014
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Location: India
GMAT Date: 04-30-2015
Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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23 Mar 2015, 10:14
Bunuel wrote:
Attachment:
originals (1).jpg
In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || CD, what is the value of x? Note: Figure not drawn to scale

A. 75
B. 85
C. 95
D. 105
E. 115

Kudos for a correct solution.

Number of properties come into play.
First, sum of angles in a triangle is 180. That gives us value of $$<AED = 65.$$
Second, Vertically opposite angles are equal, gives us $$<AED = <CEF = 65$$.
Again, angle sum property of a Triangle gives $$<ECF = 75$$

Third, Linear pair, gives $$< BCD = 105$$

Fourth, Sum of angles on the same side of transversal BC (AB parallel CD) is supplementary, gives $$<ABC=x=75$$.

Thank you.
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Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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25 Mar 2016, 07:37
Bunuel wrote:
Attachment:
originals (1).jpg
In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || CD, what is the value of x? Note: Figure not drawn to scale

A. 75
B. 85
C. 95
D. 105
E. 115

Kudos for a correct solution.

AED=CEF=65 deg

ECF=75 deg

ECF=ABC (Corresponding angles)
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Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB || [#permalink]

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14 Aug 2017, 04:22
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Re: In the figure below, ∠ADE = 60°, ∠EFC = 40°, and ∠DAE = 55°. If AB ||   [#permalink] 14 Aug 2017, 04:22
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