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In the figure CD=2OA=2OB. Find the area of the shaded region 1. ABCD i

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In the figure CD=2OA=2OB. Find the area of the shaded region 1. ABCD i  [#permalink]

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New post 28 Nov 2017, 01:21
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In the figure CD=2OA=2OB. Find the area of the shaded region
1. ABCD is a square of area 64
2. Product of the diagonals of the square ABCD is 128

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Re: In the figure CD=2OA=2OB. Find the area of the shaded region 1. ABCD i  [#permalink]

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New post 28 Nov 2017, 01:33
Sasindran wrote:
In the figure CD=2OA=2OB. Find the area of the shaded region
1. ABCD is a square of area 64
2. Product of the diagonals of the square ABCD is 128



CD=2*OA=2*OB..
Means..
OA=OB=radius
CD=DIA..

So area of quarter circle and semi circle combined =Area of circle, with DIA as side of square..

So what we require is the side of the square or distribution of circle..

Let's see what each statement tells us.
1) ABCD is a square of area 64
So side =√64=8
Sufficient
2. Product of the diagonals of the square ABCD is 128
Diagonal of square =side*√2..
Product of diagonals=side^2*√2^2=2*side^2=128.....
Side^2=64
Side=8
Sufficient

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Re: In the figure CD=2OA=2OB. Find the area of the shaded region 1. ABCD i   [#permalink] 28 Nov 2017, 01:33
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In the figure CD=2OA=2OB. Find the area of the shaded region 1. ABCD i

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