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Bunuel

In the figure, O is the center of the circle. Which one of the following must be true about the perimeter of the triangle shown?

(A) Always less than 10
(B) Always greater than 40
(C) Always greater than 30
(D) Always less than 30
(E) Less than 40 and greater than 20

Attachment:
circle.jpg
The sum of any 2 sides of a triangle must be greater than the measure of the third side

O is the centre of the triangle , So OA = OB = 10 cm

Now, AB < OB + OA

Or, AB < 10 + 10

Or, AB < 20

Say AB = 19

So, Perimeter of the Tiangle will be 10 +10 + 19 = 39 , Hence Answer must be (E)
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Bunuel

In the figure, O is the center of the circle. Which one of the following must be true about the perimeter of the triangle shown?

(A) Always less than 10
(B) Always greater than 40
(C) Always greater than 30
(D) Always less than 30
(E) Less than 40 and greater than 20

Attachment:
circle.jpg


We see that two sides of the triangle, OA and OB, must be 10 each since they are also the radii of the circle. So the 3rd side, AB, must be greater than 0 but less than 20 (the sum of the lengths of OA and OB). Therefore, the perimeter of the triangle must be greater than 10 + 10 + 0 = 20, but less than 10 + 10 + 20 = 40.

Alternate Solution:

Let’s consider the triangle AOB that is formed when A and B are just next to each other, so the distance from A to B is just slightly greater than 0. Then the perimeter of the triangle will be 10 + 10 + (negligible) = slightly greater than 20.

Now consider triangle AOB that is formed when A and B are nearly opposite each other, almost creating a diameter of the circle. In this case, the third side, AB, is nearly 20. In this case, the perimeter of the triangle is 10 + 10 + (almost 20) = just less than 40.

Thus, we see that the perimeter of triangle AOB must be less than 40 and greater than 20.

Answer: E
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