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# In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN.

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In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN.  [#permalink]

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06 Aug 2018, 00:19
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35% (medium)

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73% (01:37) correct 27% (02:06) wrong based on 34 sessions

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In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN. What is the area of the triangle RAD

1. Area of triangle CBS = 85
2. Area of triangle RAC = 50

Source: Experts Global

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In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN.  [#permalink]

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06 Aug 2018, 01:21
pushpitkc wrote:
Attachment:
Geometry_1.JPG

In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN. What is the area of the triangle RAD

1. Area of triangle CBS = 85
2. Area of triangle RAC = 50

Source: Experts Global

Since PQ || MN, hence distance between the two lines is same.

Question stem:- What is the area of the triangle RAD?
Area=$$\frac{1}{2}$$*base*height=1/2*(RC+CD)*height=$$\frac{1}{2}$$*(10+5)*height=$$\frac{1}{2}$$*15*height
So, the only unknown parameter to determine area is height. The statement that will provide the measure of height would be sufficient.

St1:-Area of triangle CBS = 85
Or, $$\frac{1}{2}$$*(CD+DS)*height=85
Or, $$\frac{1}{2}$$*17*height=85
So, height can be determined.
Sufficient.

St2:-Area of triangle RAC = 50
Or, $$\frac{1}{2}$$*10*height=50
So, height can be determined.
Sufficient.

Ans. (D)
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Re: In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN.  [#permalink]

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06 Aug 2018, 03:04
pushpitkc wrote:
Attachment:
Geometry_1.JPG

In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN. What is the area of the triangle RAD

1. Area of triangle CBS = 85
2. Area of triangle RAC = 50

Source: Experts Global

its interesting question..

area of triangle is >> 1/2 * base * height

as two lines are parallel height will remain same, figure for base is available.

either of the statement can be used to crack the answer. hence, "d"
Re: In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN.   [#permalink] 06 Aug 2018, 03:04
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# In the figure shown, RC = 10, CD = 5, DS = 12 and PQ || MN.

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