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In the figure to the right, O is both the center of the circle with ra

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SVP
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In the figure to the right, O is both the center of the circle with ra  [#permalink]

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New post 22 May 2017, 11:14
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In the figure BELOW, O is both the center of the circle with radius 2 and a vertex of the square OPRS. What is the length of diagonal PS?

(A) 1/2
(B) \(\sqrt{2}\)/2
(C) 4
(D) 2
(E) 2 \(\sqrt{5}\)

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Re: In the figure to the right, O is both the center of the circle with ra  [#permalink]

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New post 23 May 2017, 22:58
Its a square.So diagonals are of equal length.

SP = RO
But RO is the radius of circle

Hence SP = 2
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Re: In the figure to the right, O is both the center of the circle with ra  [#permalink]

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New post 24 May 2017, 18:06
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Radius of circle OR= 2
OR=PS (Diagonals of square are equal in length)
Therefore, Length of diagonal PS= 2

Answer: D.


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Re: In the figure to the right, O is both the center of the circle with ra  [#permalink]

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New post 24 May 2017, 21:10
SajjadAhmad wrote:
In the figure BELOW, O is both the center of the circle with radius 2 and a vertex of the square OPRS. What is the length of diagonal PS?

(A) 1/2
(B) \(\sqrt{2}\)/2
(C) 4
(D) 2
(E) 2 \(\sqrt{5}\)

Nova GMAT


Radius is 2 in the above figure.
Connect O to R. OR is radius of the circle. OR = 2.
OR is also diagonal of square OPRS.
PS is equal to OR.
Hence length of Diagonal PS = 2
Answer D...
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Re: In the figure to the right, O is both the center of the circle with ra  [#permalink]

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New post 18 Dec 2018, 22:16
From the figure, we can see that OR is the radius of circle and also the diagonal of square OPRS.
Since the radius of circle is given 2, the length of OR is 2.
We know that both the diagonals of square should be of same length.
Hence, PS = OR = 2.
Hence, d is the answer.
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Re: In the figure to the right, O is both the center of the circle with ra &nbs [#permalink] 18 Dec 2018, 22:16
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In the figure to the right, O is both the center of the circle with ra

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