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31 Mar 2019, 08:43
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (02:11) correct
26%
(02:33)
wrong
based on 43
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In the flat triangular surface depicted above, if x = \(\sqrt{6}\) feet, what is the area of the surface in square feet?
A. \(\sqrt{3}/8\)
B. \(\frac{3}{8}\)
C. \(3 \sqrt{3}/8\)
D. \(\frac{3}{4}\)
E. \(3 \sqrt{3}/4\)
Source: McGraw-Hill's GMAT
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31 Mar 2019, 09:07
Kudos
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As you might guess seeing the √3 in the triangle, it is a 30-60-90 triangle -- the two long sides are in a √3 to 2 ratio, so the ratio of the three sides must be 1 to √3 to 2, and the shortest side must be x/2. So the area of the triangle is (1/2)(b*h) = (1/2)(x/2)(√3x/2) = √3 x^2 / 8. Since x = √6, this is equal to (√3)(√6)^2/8 = 6√3/8 = 3√3/4.
Archit3110
Major Poster
31 Mar 2019, 10:19
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base of triangle can be found using Pythagorus viz.. x/2
so x= v6
area ;
1/2 * √6/2 * √6*√3/2
we get
\(3 \sqrt{3}/4\)
IMO E
so x= v6
area ;
1/2 * √6/2 * √6*√3/2
we get
\(3 \sqrt{3}/4\)
IMO E
SajjadAhmad
